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ios - Objective-C 不兼容的指针类型用类型为 'XYZShoutingPerson *' 的表达式初始化 'XYZPerson *'

转载 作者:可可西里 更新时间:2023-11-01 06:24:47 25 4
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我正在浏览 Programming with Objective-C教程,我已经开始尝试为 XYZPerson 实现类工厂方法

在我尝试用名为 XYZShoutingPerson 的子类实例化一个对象之前,一切看起来都很好。我在 main.m

中收到以下错误

不兼容的指针类型用类型为“XYZPerson *”的表达式初始化“XYZShoutingPerson *”

XYZPerson.h

#import <Foundation/Foundation.h>

@interface XYZPerson : NSObject

@property NSString *firstName;
@property NSString *lastName;
@property NSDate *dateOfBirth;

+ (XYZPerson *)person;

- (void)sayHello;
- (void)saySomething:(NSString *)greeting;

@end

XYZPerson.m

    #import "XYZPerson.h"

@implementation XYZPerson

+ (id)person
{
return [[self alloc] init];
}

- (void)sayHello
{
[self saySomething:@"Hello, World!"];
}

- (void)saySomething:(NSString *)greeting
{
NSLog(@"%@", greeting);
}

@end

XYZShoutingPerson.h

#import "XYZPerson.h"

@interface XYZShoutingPerson : XYZPerson
@end

XYZShoutingPerson.m

 #import "XYZShoutingPerson.h"

@implementation XYZShoutingPerson

- (void)saySomething:(NSString *)greeting
{
NSString *uppercaseGreeting = [greeting uppercaseString];
[super saySomething:uppercaseGreeting];
}

@end

主.m

#import <Foundation/Foundation.h>   
#import "XYZPerson.h"
#import "XYZShoutingPerson.h"

int main(int argc, const char * argv[])
{
@autoreleasepool {
// insert code here...
XYZPerson *newPerson = [XYZPerson person];
[newPerson sayHello];
XYZShoutingPerson *shoutingPerson = [XYZShoutingPerson person];
[shoutingPerson sayHello];
}
return 0;
}

如有任何帮助,我们将不胜感激。

谢谢!

最佳答案

错误是您正在将 XYZPerson 向下转换为 XYZShoutingPerson,这需要显式转换。

您应该做的是更改方法返回类型以使其匹配。

+ (XYZPerson *)person; 应该是 + (instancetype)person;

参见 http://clang.llvm.org/docs/LanguageExtensions.html#objective-c-features了解更多详情

关于ios - Objective-C 不兼容的指针类型用类型为 'XYZShoutingPerson *' 的表达式初始化 'XYZPerson *',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19915844/

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