gpt4 book ai didi

ios - 使用 Swift 3 获取 iPhone 或 iPad 设备的 IP 地址

转载 作者:可可西里 更新时间:2023-11-01 06:18:24 24 4
gpt4 key购买 nike

<分区>

如何使用 Swift 3 编程语言在不使用任何第三方库的情况下检索设备的 IP 地址?我使用了以下代码来获取 IP 地址:

func getIPAddress() -> String? {
var address : String?

var ifaddr : UnsafeMutablePointer<ifaddrs> = nil
if getifaddrs(&ifaddr) == 0 {

var ptr = ifaddr
while ptr != nil {
defer { ptr = ptr.memory.ifa_next }

let interface = ptr.memory

let addrFamily = interface.ifa_addr.memory.sa_family
if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {

if let name = String.fromCString(interface.ifa_name) where name == "en0" {

var hostname = [CChar](count: Int(NI_MAXHOST), repeatedValue: 0)
getnameinfo(interface.ifa_addr, socklen_t(interface.ifa_addr.memory.sa_len),
&hostname, socklen_t(hostname.count),
nil, socklen_t(0), NI_NUMERICHOST)
address = String.fromCString(hostname)
}
}
}

freeifaddrs(ifaddr)
}

return address
}

但是 UnsafeMutablePointer<ifaddrs>语法不起作用。它会引发语法错误。我是否需要导入一个框架来尝试帮助我?

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com