ios - Objective-C:将字符串参数传递给 taggesture @selector

Question

我想要实现的是:当我点击一个特定的 UIImageView 时，UITapGesture 会将一个字符串传递给 tap 方法。

我的代码如下:假设我已经有一个 UIImageView 对象，当我点击这个图像时，它会调用电话，

UITapGestureRecognizer *tapFirstGuy = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(makeCallToThisPerson:@"1234567")];
[imageViewOne addGestureRecognizer:tapFirstGuy];

- (void)makeCallToThisPerson:(NSString *)phoneNumber
{
    NSString *phoneNum = [NSString stringWithFormat:@"tel:%@", phoneNumber];
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNum]];
}

但是，我收到以下编译错误:@selector(makeCallToThisPerson:@"1234567");

我不知道发生了什么。为什么我不能将字符串传递给私有(private)方法？

Answer 1

还有一种方法可以尝试编写 UITapGestureRecognizer 的子类，如下所示:-

@interface customTapGestureRecognizer : UITapGestureRecognizer

@property (nonatomic, strong) NSString * phoneNumber;

@end


// customTapGestureRecognizer.m

@implementation customTapGestureRecognizer

@end


// =====================

....

customTapGestureRecognizer *singleTap = [[customTapGestureRecognizer alloc] initWithTarget:self action:@selector(makeCallToThisPerson:)];

singleTap.phoneNumber = @"1234567";


-(void) makeCallToThisPerson:(UITapGestureRecognizer *)tapRecognizer {

customTapGestureRecognizer *tap = (customTapGestureRecognizer *)tapRecognizer;

NSLog(@"phoneNumber : %@", tap.phoneNumber);

}

注意:- 编写子类的优点是您可以在 UITapGestureRecognizer 中轻松传递更多数据。