ios - Whatsapp URL 方案中的 ABID

Question

昨天 Whatsapp 更新了他们的 iOS 应用程序并发布了官方 URL 方案(api hooks)。

我想尝试一下它，但我现在面临的问题是我不理解整个“abid”的东西？!我从哪里获得联系人 ID？那我该如何使用它呢？

提前致谢:)

Answer 1

ABID代表Address book Record ID，下面的代码用于获取AB Record ID。它对 URL 本身中分隔符的使用很敏感。所以最初的试验没有奏效。要向特定用户发送注释，请使用此 - urlstring 格式: whatsapp://send?abid=123&text=What%20a%20nice%20day - 注意使用 & 标记第二个参数。

- (BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController    *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person
{   
    QR_whatsappABID  = (ABRecordID)ABRecordGetRecordID(person);
    ....
    QR_whatsapp_string = [NSString stringWithFormat:@"whatsapp://send?abid=%d&text=%@;",QR_whatsappABID, outmessage];
    ....
}

这可以在不使用人员选择器的情况下进行编码，只需打开地址簿即可:

比较姓名或姓名和号码，一项一项地查看记录 -

ABAddressBookRef addressBook = ABAddressBookCreateWithOptions (NULL, error);
int len = (int)ABAddressBookGetPersonCount(addressBook);
for(int i = 1; i < (len + 1); i++) {
    ABRecordRef person = ABAddressBookGetPersonWithRecordID(addressBook, (ABRecordID)i);
    NSString *first, *last;
    if (!person) {
        continue;
    }
    CFStringRef firstc = (CFStringRef)ABRecordCopyValue(person, kABPersonFirstNameProperty);
    if (firstc) {
        CFStringRef lastc =(CFStringRef) ABRecordCopyValue(person, kABPersonLastNameProperty);
        if (lastc) {
            first = [NSString stringWithFormat:@"%@",firstc];
            last =[NSString stringWithFormat:@"%@",lastc];
            CFRelease(lastc);
        }
        CFRelease(firstc);
    }
    if ([[first lowercaseString] isEqualToString:[firstname lowercaseString]] && [[last lowercaseString] isEqualToString:[surname lowercaseString]]) {
        alreadyExists = YES;
        ABID = ABRecordGetRecordID(person);
        break;
    }
}