ios - Objective-C HTTP POST 请求

Question

我正在使用一个使用 HTTP 的 SMS 网关。我使用有关 stackoverflow 等的教程和问题创建了一个请求，但出了点问题。当我手动输入 URL 时，我可以毫无问题地使用网关，但我无法以编程方式执行此操作，所以我认为我的代码可能不正确。感谢任何帮助!

NSString *post = [NSString stringWithFormat:@"user=%@&password=%@&api_id=%@&to=%@&text=%@",_username,_password,_apiID,[_numbers componentsJoinedByString:@","],_txtMsg.text];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:@"http://api.mySmsGateWay.com/http/sendmsg"]];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:postData];
NSError *error = [[NSError alloc] init];
NSHTTPURLResponse *responseCode = nil;

NSData *oResponseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&responseCode error:&error];

if([responseCode statusCode] != 200){
    NSLog(@"Error getting, HTTP status code %i", [responseCode statusCode]);
}

NSLog (@"%@", [[NSString alloc] initWithData:oResponseData encoding:NSUTF8StringEncoding]);

Answer 1

NSMutableURLRequest *urlRequest = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://api.mySmsGateWay.com/http/sendmsg"]];

NSString *userUpdate =[NSString stringWithFormat:@"user=%@&password=%@&api_id=%@&to=%@&text=%@",_username,_password,_apiID,[_numbers componentsJoinedByString:@","],_txtMsg.text, nil];

//create the Method "GET" or "POST"
[urlRequest setHTTPMethod:@"POST"];

//Convert the String to Data
NSData *data1 = [userUpdate dataUsingEncoding:NSUTF8StringEncoding];

//Apply the data to the body
[urlRequest setHTTPBody:data1];

NSURLSession *session = [NSURLSession sharedSession];
NSURLSessionDataTask *dataTask = [session dataTaskWithRequest:urlRequest completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
    NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response;
    if(httpResponse.statusCode == 200)
    {
        NSError *parseError = nil;
        NSDictionary *responseDictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
        NSLog(@"The response is - %@",responseDictionary);
        NSInteger success = [[responseDictionary objectForKey:@"success"] integerValue];
        if(success == 1)
        {
            NSLog(@"Login SUCCESS");
        }
        else
        {
            NSLog(@"Login FAILURE");
        }
    }
    else
    {
        NSLog(@"Error");     
    }
}];
[dataTask resume];