iOS CGRect 在另一个 CGRect 里面

Question

有人对以下任务有好的解决方案吗？

我需要检查一个 CGRect 是否在另一个 CGRect 内部并返回一个 CGPoint，如果矩形窗口在包含的任何维度之外，它会给出偏移量。

提前致谢

Answer 1

Swift 4.1

// Returns how much is the rect outside of the view, 0 if inside
func isRectVisibleInView(rect: CGRect, inRect: CGRect) -> CGPoint {
    var offset = CGPoint()

    if inRect.contains(rect) {
        return CGPoint(x: 0, y: 0)
    }

    if rect.origin.x < inRect.origin.x {
        // It's out to the left
        offset.x = inRect.origin.x - rect.origin.x
    } else if (rect.origin.x + rect.width) > (inRect.origin.x + inRect.width) {
        // It's out to the right
        offset.x = (rect.origin.x + rect.width) - (inRect.origin.x + inRect.width)
    }

    if rect.origin.y < inRect.origin.y {
        // It's out to the top
        offset.y = inRect.origin.y - rect.origin.y
    } else if rect.origin.y + rect.height > inRect.origin.y + inRect.height {
        // It's out to the bottom
        offset.y = (rect.origin.y + rect.height) - inRect.origin.y + inRect.height
    }


    return offset
}

Swift 3 update

// Returns how much is the rect outside of the view, 0 if inside
func isRectVisibleInView(rect: CGRect, inRect: CGRect) -> CGPoint {
    var offset = CGPoint()

    if CGRectContainsRect(inRect, rect) {
        return CGPointMake(0, 0)
    }

    if rect.origin.x < inRect.origin.x {
        // It's out to the left
        offset.x = inRect.origin.x - rect.origin.x
    } else if (rect.origin.x + rect.width) > (inRect.origin.x + inRect.width) {
        // It's out to the right
        offset.x = (rect.origin.x + rect.width) - (inRect.origin.x + inRect.width)
    }

    if rect.origin.y < inRect.origin.y {
        // It's out to the top
        offset.y = inRect.origin.y - rect.origin.y
    } else if rect.origin.y + rect.height > inRect.origin.y + inRect.height {
        // It's out to the bottom
        offset.y = (rect.origin.y + rect.height) - inRect.origin.y + inRect.height
    }


    return offset
}