gpt4 book ai didi

ios - PayUMoney 支付网关问题

转载 作者:可可西里 更新时间:2023-11-01 03:36:41 25 4
gpt4 key购买 nike

我必须在我的 iOS 应用程序中集成 PayUMoney 支付网关。他们没有适用于 iOS 的 SDK。所以我必须在 webview 中加载一些 web URL 来支付。我的参数是

int i = arc4random() % 9999999999;
NSString *strHash = [self createSHA512:[NSString stringWithFormat:@"%d%@",i,[NSDate date]]];// Generatehash512(rnd.ToString() + DateTime.Now);
NSString *txnid1 = [strHash substringToIndex:20];
NSLog(@"tnx1 id %@",txnid1);
NSString *key = @"JBZaLc";
NSString *amount = @"1000";
NSString *productInfo = @"Nice product";
NSString *firstname = @"Mani";
NSString *email = @"mani.ingenius@gmail.com";
NSString *phone = @"1234566";
NSString *surl = @"www.google.com";
NSString *furl = @"www.google.com";
NSString *serviceprovider = @"payu_paisa";
NSString *action = @"https://test.payu.in/_payment";
NSString *hashValue = [NSString stringWithFormat:@"%@|%@|%@|%@|%@|%@|udf1|udf2|udf3|udf4|udf5||||||salt",key,txnid1,amount,productInfo,firstname,email];
NSString *hash = [self createSHA512:hashValue];
NSDictionary *parameters = [NSDictionary dictionaryWithObjects:[NSArray arrayWithObjects:txnid1,key,amount,productInfo,firstname,email,phone,surl,furl,hash,serviceprovider,action, nil] forKeys:[NSArray arrayWithObjects:@"txnid",@"key",@"amount",@"productinfo",@"firstname",@"email",@"phone",@"surl",@"furl",@"hash",@"service_provider",@"action", nil]];

我必须对我的测试 URL (https://test.payu.in/_payment) 使用 POST 方法并且需要传递参数。我在字典(“参数”)中有所有带有键和值的参数。所以我尝试了以下代码

 NSData *dataValue = [self getPropertiesAsData:parameters];
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"https://test.payu.in/_payment"]];
// Create a mutable copy of the immutable request and add more headers
NSMutableURLRequest *mutableRequest = [request mutableCopy];
[mutableRequest setHTTPMethod: @"POST"];
[mutableRequest setHTTPBody: dataValue];
request = [mutableRequest copy];
[_webviewSample loadRequest:request];


-(NSData *)getPropertiesAsData :(NSDictionary *)dict{
NSMutableData *body = [NSMutableData postData];
[dict enumerateKeysAndObjectsUsingBlock:^(id key, id obj, BOOL *stop) {
[body addValue:[obj stringByReplacingOccurrencesOfString:@" " withString:@"%20"] forKey:key];
}];
return body;
}

-(NSString *)createSHA512:(NSString *)string
{
const char *cstr = [string cStringUsingEncoding:NSUTF8StringEncoding];
NSData *data = [NSData dataWithBytes:cstr length:string.length];
uint8_t digest[CC_SHA512_DIGEST_LENGTH];
CC_SHA512(data.bytes, data.length, digest);
NSMutableString* output = [NSMutableString stringWithCapacity:CC_SHA512_DIGEST_LENGTH * 2];
for(int i = 0; i < CC_SHA512_DIGEST_LENGTH; i++)
[output appendFormat:@"%02x", digest[i]];
return output;
}

但是当我运行它时,它说“缺少强制参数 tnxid”。但是我已经传递了你可以在参数字典中看到的 tnxid。如果我正确地传递了所有内容,那么结果将是用户可以在其中选择银行详细信息等的网页,我必须将其加载到我的 WebView 中。

请帮我找出我做错了什么或者我应该怎么做才能得到正确的结果。

最佳答案

我成功找到了答案。下面列出了我的工作代码

int i = arc4random() % 9999999999;
NSString *strHash = [self createSHA512:[NSString stringWithFormat:@"%d%@",i,[NSDate date]]];// Generatehash512(rnd.ToString() + DateTime.Now);
NSString *txnid1 = [strHash substringToIndex:20];
NSLog(@"tnx1 id %@",txnid1);
NSString *key = @"JBZaLc";
NSString *amount = @"1000";
NSString *productInfo = @"Nice product";
NSString *firstname = @"Mani";
NSString *email = @"mani.ingenius@gmail.com";
NSString *phone = @"1234566";
NSString *surl = @"www.google.com";
NSString *furl = @"www.google.com";
NSString *serviceprovider = @"payu_paisa";


NSString *hashValue = [NSString stringWithFormat:@"%@|%@|%@|%@|%@|%@|||||||||||GQs7yium",key,txnid1,amount,productInfo,firstname,email];
NSString *hash = [self createSHA512:hashValue];
NSDictionary *parameters = [NSDictionary dictionaryWithObjects:[NSArray arrayWithObjects:txnid1,key,amount,productInfo,firstname,email,phone,surl,furl,hash,serviceprovider
, nil] forKeys:[NSArray arrayWithObjects:@"txnid",@"key",@"amount",@"productinfo",@"firstname",@"email",@"phone",@"surl",@"furl",@"hash",@"service_provider", nil]];
__block NSString *post = @"";
[parameters enumerateKeysAndObjectsUsingBlock:^(id key, id obj, BOOL *stop) {
if ([post isEqualToString:@""]) {
post = [NSString stringWithFormat:@"%@=%@",key,obj];
}else{
post = [NSString stringWithFormat:@"%@&%@=%@",post,key,obj];
}

}];

NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%lu",(unsigned long)[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:[NSString stringWithFormat:@"https://test.payu.in/_payment"]]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];
[request setHTTPBody:postData];

[_webviewSample loadRequest:request];

然后要用到的函数

-(NSString *)createSHA512:(NSString *)string
{
const char *cstr = [string cStringUsingEncoding:NSUTF8StringEncoding];
NSData *data = [NSData dataWithBytes:cstr length:string.length];
uint8_t digest[CC_SHA512_DIGEST_LENGTH];
CC_SHA512(data.bytes, (CC_LONG)data.length, digest);
NSMutableString* output = [NSMutableString stringWithCapacity:CC_SHA512_DIGEST_LENGTH * 2];
for(int i = 0; i < CC_SHA512_DIGEST_LENGTH; i++)
[output appendFormat:@"%02x", digest[i]];
return output;
}

关于ios - PayUMoney 支付网关问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27898349/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com