ios - 如何在 iOS 8+ 的 iPhone 上以编程方式配置和显示弹出窗口

Question

如何在 iOS 8 中仅使用 Objective-C 代码，不使用 Story Boards 或其他 Interface Builder 工件，在 iPhone(所有尺寸和方向)的弹出窗口中呈现 UIViewController。

Answer 1

在 iOS 8 中，您可以将任何 View Controller 配置为显示为弹出窗口，如下所示:

UIViewController* controller = ...; // your initialization goes here

// set modal presentation style to popover on your view controller
// must be done before you reference controller.popoverPresentationController
controller.modalPresentationStyle = UIModalPresentationPopover;
controller.preferredContentSize = CGSizeMake(150, 300);

// configure popover style & delegate
UIPopoverPresentationController *popover =  controller.popoverPresentationController;
popover.delegate = controller;
popover.sourceView = sourceView;
popover.sourceRect = CGRectMake(150,300,1,1);
popover.permittedArrowDirections = UIPopoverArrowDirectionAny;

// display the controller in the usual way
[self presentViewController:controller animated:YES completion:nil];

为了让它在 iPhone 上显示为弹出窗口，请将其添加到弹出窗口(您在上面设置的)的 UIPopoverPresentationControllerDelegate 委托(delegate)中:

- (UIModalPresentationStyle)adaptivePresentationStyleForPresentationController:(UIPresentationController *)controller
{
    return UIModalPresentationNone;
}