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ios - 在 'tag' 类型的对象上找不到属性 '_strong id'

转载 作者:可可西里 更新时间:2023-11-01 03:26:56 28 4
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我正在根据本教程 (http://bit.ly/NI9kQe) 构建一个应用程序,它使用自定义 Web API 连接到 Web 服务器。其中一项要求是检测是否点击了登录或注册按钮。这是使用在界面生成器中为按钮设置的“标签”完成的(注册按钮的标签为 1)。

代码块位于 btnLoginRegisterTapped 方法中,如下所示(错误发生在 -> NSString* command = (sender.tag==1)?@"register":@"login"; 行):

- (IBAction)btnLoginRegisterTapped:(id)sender {

//form fields validation
if (fldUserName.text.length < 4 || fldPassword.text.length < 4) {
// [UIAlertView error:@"Enter username and password over 4 chars each."];

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Opps!!" message:@"Enter username and password over 4 chars each." delegate:self cancelButtonTitle:@"Cancel" otherButtonTitles:nil];
// optional - add more buttons:
[alert addButtonWithTitle:@"Yes"];
[alert show];
return;

}

//salt the password
NSString* saltedPassword = [NSString stringWithFormat:@"%@%@", fldPassword.text, kSalt];

//prepare the hashed storage
NSString* hashedPassword = nil;
unsigned char hashedPasswordData[CC_SHA1_DIGEST_LENGTH];

//hash the pass
NSData *data = [saltedPassword dataUsingEncoding: NSUTF8StringEncoding];
if (CC_SHA1([data bytes], [data length], hashedPasswordData)) {
hashedPassword = [[NSString alloc] initWithBytes:hashedPasswordData length:sizeof(hashedPasswordData) encoding:NSASCIIStringEncoding];
} else {

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Opps!!" message:@"Password cannot be reset!" delegate:self cancelButtonTitle:@"Cancel" otherButtonTitles:nil];
// optional - add more buttons:
[alert addButtonWithTitle:@"Yes"];
[alert show];
return;
}

//************ THIS IS WHERE THE ERROR OCCURS *****************//
//check whether it's a login or register
NSString* command = (sender.tag==1)?@"register":@"login";
NSMutableDictionary* params =[NSMutableDictionary dictionaryWithObjectsAndKeys:
command, @"command",
fldUserName.text, @"username",
hashedPassword, @"password",
nil];

//make the call to the web API
[[API sharedInstance] commandWithParams:params
onCompletion:^(NSDictionary *json) {
//handle the response
//result returned
NSDictionary* res = [[json objectForKey:@"result"] objectAtIndex:0];

if ([json objectForKey:@"error"]==nil && [[res objectForKey:@"IdUser"] intValue]>0) {
//success
[[API sharedInstance] setUser: res];
[self.presentingViewController dismissViewControllerAnimated:YES completion:nil];

//show message to the user
[[[UIAlertView alloc] initWithTitle:@"Logged in"
message:[NSString stringWithFormat:@"Welcome %@",[res objectForKey:@"username"] ]
delegate:nil
cancelButtonTitle:@"Close"
otherButtonTitles: nil] show];

} else {
//error

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Opps!!" message:@"Server down? Try Again" delegate:self cancelButtonTitle:@"Cancel" otherButtonTitles:nil];
// optional - add more buttons:
[alert addButtonWithTitle:@"Yes"];
[alert show];
return;

}

}];

当我尝试构建项目(实际上是工作区)时出现错误:

在“_strong id”类型的对象上找不到属性“标签”

我正在使用 xcode 5.0 为 iOS7 部署。

谢谢,

最佳答案

属性语法不能与通用 id 类型的变量一起使用。

因此,要么用方法调用 [sender tag] 替换 sender.tag,要么更好,在方法定义中使用 sender 参数的实际类型:

- (IBAction)btnLoginRegisterTapped:(UIButton *)sender { ... }

提示:在 Xcode 中使用“Control-Drag”创建 Action 时,使用“类型”字段中的弹出窗口选择发件人的实际类型。然后使用正确的参数类型创建操作方法。

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关于ios - 在 'tag' 类型的对象上找不到属性 '_strong id',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19641751/

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