iphone - 你如何枚举一组 block ？

Question

self.myArray = @[ [^{ NSLog(@"a"); } copy],
                  [^{ NSLog(@"b"); } copy]];

……以后……

[self.myArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    // This syntax is wrong, but I hope you get my intention
    void (^) (void) block = obj;  
    block();
}];

枚举时如何抛出 block ？ (如果你能在没有 typedef 的情况下做到这一点，那就加分了)

Answer 1

[self.myArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    void (^block)() = obj;  
    block();
}];

或者直接在参数列表中:

[self.myArray enumerateObjectsUsingBlock:^(void (^block)(), NSUInteger idx, BOOL *stop) {
    block();
}];