javascript - 定位上下文菜单

Question

我正在尝试使用 jQuery 定位自定义上下文菜单。
它第一次出现在正确的位置(鼠标坐标)，但随后当前位置与新位置相加，因此菜单从屏幕上消失。
这是 JavaScript:

<script>
$(function(){
    $('#box').hide();

    $(document).bind("contextmenu", function(e) {
        $("#box").offset({left:e.pageX, top:e.pageY});
        $('#box').show();
        e.preventDefault();
    });

    $(document).bind("click", function(e) {
        $('#box').hide();
    });
    $('#box').bind("click", function(e) {
        $('#box').hide();
    });
});
</script>

Answer 1

尝试位置:固定；上下文菜单的位置根据以下条件更改 -

var windowHeight = $(window).height()/2;
var windowWidth = $(window).width()/2;
if(e.clientY > windowHeight && e.clientX <= windowWidth) {
  $("#contextMenuContainer").css("left", e.clientX);
  $("#contextMenuContainer").css("bottom", $(window).height()-e.clientY);
  $("#contextMenuContainer").css("right", "auto");
  $("#contextMenuContainer").css("top", "auto");
} else if(e.clientY > windowHeight && e.clientX > windowWidth) {
  $("#contextMenuContainer").css("right", $(window).width()-e.clientX);
  $("#contextMenuContainer").css("bottom", $(window).height()-e.clientY);
  $("#contextMenuContainer").css("left", "auto");
  $("#contextMenuContainer").css("top", "auto");
} else if(e.clientY <= windowHeight && e.clientX <= windowWidth) {
  $("#contextMenuContainer").css("left", e.clientX);
  $("#contextMenuContainer").css("top", e.clientY);
  $("#contextMenuContainer").css("right", "auto");
  $("#contextMenuContainer").css("bottom", "auto");
} else {
  $("#contextMenuContainer").css("right", $(window).width()-e.clientX);
  $("#contextMenuContainer").css("top", e.clientY);
  $("#contextMenuContainer").css("left", "auto");
  $("#contextMenuContainer").css("bottom", "auto");
}

http://jsfiddle.net/AkshayBandivadekar/zakn7Lwb/14/