JavaScript 错误 : Cannot read property 'parentNode' of null

Question

我正在使用的 javascript:

javascript: c = '{unit}, ({coords}) {player} |{distance}| {return}';
p = ['Scout', 'LC', 'HC', 'Axe', 'Sword', 'Ram', '***Noble***'];

function V() {
    return 1;
}
window.onerror = V;

function Z() {
    d = (window.frames.length > 0) ? window.main.document : document;
    aid = d.getElementById('editInput').parentNode.innerHTML.match(/id\=(\d+)/)[1];

    function J(e) {
        vv = e.match(/\d+\|\d+/g);
        return (vv ? vv[vv.length - 1].match(/((\d+)\|(\d+))/) : null);
    }
    function K(e) {
        f = parseInt(e, 10);
        return (f > 9 ? f : '0' + f);
    }
    function L(g, e) {
        return g.getElementsByTagName(e);
    }
    function N(g) {
        return g.innerHTML;
    }
    function M(g) {
        return N(L(g, 'a')[0]);
    }
    function O() {
        return k.insertRow(E++);
    }
    function W(f) {
        return B.insertCell(f);
    }
    function P(g, e) {
        g.innerHTML = e;
        return g;
    }
    function X(e) {
        C = B.appendChild(d.createElement('th'));
        return P(C, e);
    }
    function Y(f) {
        return K(f / U) + ':' + K(f % (U) / T) + ':' + K(f % T);
    }
    U = 3600;
    T = 60;
    R = 'table';
    S = 'width';
    s = L(document, R);
    for (j = 0; j < s.length; j++) {
        s[j].removeAttribute(S);
        if (s[j].className == 'main') {
            s = L(L(s[j], 'tbody')[0], R);
            break;
        }
    }
    D = 0;
    for (j = 0; j < s.length; j++) {
        s[j].removeAttribute(S);
        if (s[j].className = 'vis') {
            k = s[j];
            if (t = k.rows) {
                D = t.length;
                break;
            }
        }
    }
    for (E = 0; E < D; E++) {
        l = t[E];
        m = (u = l.cells) ? u.length : 0;
        if (m) {
            u[m - 1].colSpan = 5 - m;
            if (N(u[0]) == 'Arrival:') {
                Q = new Date(N(u[1]).replace(/<.*/i, ''));
            } else {
                if (N(u[0]) == 'Arrival in:') {
                    v = N(u[1]).match(/\d+/ig);
                }
            }
            if (E == 1) {
                G = M(u[2]);
            }
            if (E == 2) {
                w = J(M(u[1]));
            }
            if (E == 4) {
                x = J(M(u[1]));
            }
        }
    }
    y = v[0] * U + v[1] * T + v[2] * 1;
    n = w[2] - x[2];
    o = w[3] - x[3];
    F = Math.sqrt(n * n + o * o);
    H = F.toFixed(2);
    E = D - 2;
    s = L(k, 'input');
    i = s[1];
    h = s[0];
    h.size = T;
    B = O();
    P(W(0), 'Distance:').colSpan = 2;
    P(W(1), H + ' Fields').colSpan = 2;
    B = O();
    X('Unit');
    X('Sent');
    X('Duration');
    X('Name to');
    c = c.replace(/\{coords\}/i, w[1]).replace(/\{distance\}/i, H).replace(/\{player\}/i, G);
    for (j in p) {
        z = Math.round([9.00000000, 10.00000000, 11.00000000, 18.0000000015, 22.00000000, 30.00000000, 35.0000000][j] * T * F);
        A = z - y;
        if (A > 0) {
            I = Y(z);
            B = O();
            P(W(0), p[j]);
            P(W(1), A < T && 'just now' || A < U && Math.floor(A / T) + ' mins ago' || Y(A) + ' ago');
            P(W(2), I);
            C = W(3);
            q = C.appendChild(i.cloneNode(1));
            r = C.appendChild(h.cloneNode(1));
            r.id = 'I' + j;
            r.value = c.replace(/\{duration\}/i, I).replace(/\{sent\}/i, new Date(Q.valueOf() - z * 1000).toLocaleString().replace(/.\d{4}/i, '').replace(/(\w{3})\w*/i, '$1')).replace(/\{return\}/i, new Date(Q.valueOf() + z * 1000).toString().replace(/\w+\s*/i, '').replace(/(\d*:\d*:\d*)(.*)/i, '$1')).replace(/\{unit\}/i, p[j]).replace(/\{attack_id\}/i, aid);
            q.onmousedown = new Function('h.value=d.getElementById(\'I' + j + '\').value;');
        }
    }
}
Z();

我收到的错误:

Uncaught TypeError: Cannot read property 'parentNode' of null

URL 如下所示:

game.php?village=2100&id=4348754&type=other&screen=info_command

Answer 1

有两种可能:

1. editInput是错字，该元素的实际 ID 不同(ID 区分大小写)。
2. 您正在执行这段代码，而 DOM 还没有准备好。为防止这种情况，请在 </body> 之前执行代码结束标记，或将其包装在 load 的事件处理程序中window的事件或 DOMContentLoaded document的事件.

已编辑 如何包装您的代码:

window.onload = function() {
    //your code here
};