Python socketserver，如何获取自己的tcp端口号

Question

我需要用socketserver搭建一个tcp server。根据他们的文档，我需要继承类 TCPServer，并将它传递给类 BaseRequestHandler 的子类，我重写了方法 handle()。

现在我需要在不同的端口上构建两个服务器，有没有办法在 handle() 函数中，(否则我必须设置两个几乎相同的处理程序类，这不是我想要的)，我可以得到我自己的端口号？

Answer 1

不要在handle() 方法中执行，将端口号传入(来自https://docs.python.org/2/library/socketserver.html#socketserver-tcpserver-example ):

#!/usr/bin/env python

import SocketServer, argparse

class MyTCPHandler(SocketServer.BaseRequestHandler):
    """
    The RequestHandler class for our server.

    It is instantiated once per connection to the server, and must
    override the handle() method to implement communication to the
    client.
    """

    def handle(self):
        # self.server.server_address is a tuple (IP, port) the server is listening on                                                       
        (host, port) = self.server.server_address
        print 'port # is: {}'.format(port)
        # self.request is the TCP socket connected to the client
        self.data = self.request.recv(1024).strip()
        print "{} wrote:".format(self.client_address[0])
        print self.data
        # just send back the same data, but upper-cased
        self.request.sendall(self.data.upper())

if __name__ == "__main__":
    parser = argparse.ArgumentParser()
    parser.add_argument('-p', '--port', required=True, help='the TCP port to listen on')
    args = parser.parse_args()
    HOST, PORT = "localhost", int(args.port)

    # Create the server, binding to localhost on port 9999
    server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)

    # Activate the server; this will keep running until you
    # interrupt the program with Ctrl-C
    server.serve_forever()

在此示例中，您必须在使用 -p 命令行开关启动程序时提供端口号作为参数。