python - 如何在 Python 套接字聊天室中创建踢功能？

Question

这是一个套接字聊天室，客户端可以在其中相互发送消息。我想要一个踢球功能，服务器可以踢出某些人。

我已经成功地把想要的用户踢出去了，但它仍然把我踢出去，这是执行此操作的代码:

for name in keys:
    if('**kick '+name) in data:
        clients[name].close()
        del clients[name]
        found = True

我试过这个:

for name in keys:
    if('**kick '+name) in data:
        data = data.replace('**kick '+name,'')
        clients.get(name).pop
        found = True

但是当我运行这段代码并尝试它时，我反而被踢了。

这是我的完整代码:

服务器.py

import socket, threading
host = "127.0.0.1"
port = 4000
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host,port))
s.listen()
clients = {}
print("Server is ready...")
serverRunning = True
def handle_client(conn, uname):

    clientConnected = True
    keys = clients.keys()
    help = 'There are 3 commands in Messenger\n1**chatlist > gives you the list of the people currently online\n2**quit > To end your session and quit the server\n3**(username) sends a private message to any user you want'

    while clientConnected:
        try:
            response = 'Number of People Online\n'
            data = conn.recv(1024).decode('ascii')
            found = False
            if '**' not in data:
                for k,v in clients.items():
                    if v != conn:
                        v.send(data.encode('ascii'))
                        found = True


            elif '**chatlist' in data:
                clientNo = 0
                for name in keys:
                    clientNo += 1
                    response = response + str(clientNo) +'::' + name+'\n'
                conn.send(response.encode('ascii'))
                found = True


            elif '**help' in data:
                conn.send(help.encode('ascii'))
                found = True
            else:
                for name in keys:
                    if('**'+name) in data:
                        data = data.replace('**'+name,'')
                        clients.get(name).send(data.encode('ascii'))
                        found = True
                    if('**kick '+name) in data:
                        clients.get(name).pop
                        found = True
                if(not found):
                    conn.send('Trying to send message to invalid person.'.encode('ascii'))


        except:
            clients.pop(uname)
            print(uname + ' has logged out')
            clientConnected = False

while serverRunning:
    conn,addr = s.accept()
    uname = conn.recv(1024).decode('ascii')
    print('%s connected to the server'%str(uname))
    conn.send('Welcome to Messenger. Type **help to know all the commands'.encode('ascii'))

    if(conn not in clients):
        clients[uname] = conn
        threading.Thread(target = handle_client, args = (conn, uname,)).start()

客户端.py

import socket,threading
host = "127.0.0.1"
port = 4000
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host,port))
uname = input("Enter username: ")
s.send(uname.encode('ascii'))
clientRunning = True

def echo_data(sock):
   serverDown = False
   while clientRunning and (not serverDown):
      try:
         data = sock.recv(1024).decode('ascii')
         print(data)
      except:
         print('Server is Down. You are now Disconnected. Press enter to exit...')
         serverDown = True


threading.Thread(target=echo_data, args = (s,)).start()
while clientRunning:
   tempMsg = input()
   data = uname + '>> ' + tempMsg
   s.send(data.encode('ascii'))

Answer 1

clients 是一个字典。所以基本上，踢一个特定的用户意味着从客户字典中删除他的凭据。所以而不是 clients.get(name).pop
利用 clients.pop(名称)

编辑:也不要使用 for name in keys:使用 作为列表中的名称(客户):因为，您不能在遍历字典时更改字典的大小。它会抛出异常。但是，此代码只会将用户从字典中删除，而不会将您踢出。除非您从字典中获取用户的值并使用 .close()，否则用户不会被踢出。希望这有帮助