ios - 如何将 JSON 解析为 [String : AnyObject] in Swift

Question

我正在尝试执行一个简单的 JSON 字符串到对象的转换。这是代码:

let u = "somehost.com/api/1/ipa/2"
let url = NSURL(string: u )!

let data = NSData(contentsOfURL: url)!

let parsed: AnyObject? = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.AllowFragments) 

if let json = parsed as? [String: AnyObject]{
    // never enters this if statement.
}

但它不会正确展开。在我看来，这应该简单得多。有人可以帮忙吗？还使用“Xcode 7.3 和 swift 2.2”。

我想避免使用第三方库。

Answer 1

Sample Json Parsing Fetch and read 这样简单易懂的理解过程。点击下面的链接，您将看到作为字典的响应，并且字典内部有一个数组......

   let WebURL = "http://api.randomuser.me/"

    let url2 = NSURL(string:WebURL)

    let data = NSData(contentsOfURL: url2!)

    do
    {

       let dictionary = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments) as! NSMutableDictionary

        print(dictionary)

        let arrayOfValues = dictionary .objectForKey("results") as! NSMutableArray

        print(arrayOfValues)


        for var i = 0; i<arrayOfValues.count; i++ {


            let resultDictInsideArray = arrayOfValues.objectAtIndex(i)

            let NameDict = resultDictInsideArray.objectForKey("name")!

            let locDict = resultDictInsideArray.objectForKey("location")!



            print(NameDict.objectForKey("title")!)
            print(locDict.objectForKey("street")!)



        }


    }catch {

    print("error")


    }

如果您的网址有空格，请像这样为网址编写代码

 let url = NSURL(string: stringUrl.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!)!