javascript - 如何取消订阅 Angular 2中的多个订阅者

Question

我在另一个组件中有 shareService 和订阅:

import { Component, Input, OnDestroy } from '@angular/core';
import { MissionService } from './mission.service';
import { Subscription }   from 'rxjs/Subscription';
@Component({
  selector: 'my-astronaut',
  template: `
    <p>
      {{astronaut}}: <strong>{{mission}}</strong>
      <button
        (click)="confirm()"
        [disabled]="!announced || confirmed">
        Confirm
      </button>
    </p>
  `
})
export class AstronautComponent implements OnDestroy{
  @Input() astronaut: string;
  mission = "<no mission announced>";
  confirmed = false;
  announced = false;
  subscription:Subscription;

  constructor(private missionService: MissionService) {
    this.subscription = missionService.missionAnnounced$.subscribe(
      mission => {
        this.mission = mission;
        this.announced = true;
        this.confirmed = false;
    })




  }
  confirm() {
    this.confirmed = true;
    this.missionService.confirmMission(this.astronaut);
  }
  ngOnDestroy(){
    // prevent memory leak when component destroyed
    this.subscription.unsubscribe();

  }
}

我想知道我的构造函数中是否有2个订阅者，如何在ngDestroy中取消订阅两次订阅者？我应该使用 subscription2:Subscription;? 和 ngDestroy this.subscription2.unsubscribe();?这是真的吗？

Answer 1

您可以在数组中的 ngOnDestroy() 中收集要立即取消订阅的订阅

export class AstronautComponent implements OnDestroy{
  @Input() astronaut: string;
  mission = "<no mission announced>";
  confirmed = false;
  announced = false;
  subscriptions:Subscription[] = [];

  constructor(private missionService: MissionService) {
    this.subscriptions.push(missionService.missionAnnounced$.subscribe(
      mission => {
        this.mission = mission;
        this.announced = true;
        this.confirmed = false;
    }));

    this.subscriptions.push(fooService.fooObservable$.subscribe(
      ...
    }));
  }

  confirm() {
    this.confirmed = true;
    this.missionService.confirmMission(this.astronaut);
  }

  ngOnDestroy(){
    // prevent memory leak when component destroyed
    this.subscriptions.forEach(s => s.unsubscribe());
  }
}