作者热门文章
- android - RelativeLayout 背景可绘制重叠内容
- android - 如何链接 cpufeatures lib 以获取 native android 库?
- java - OnItemClickListener 不起作用,但 OnLongItemClickListener 在自定义 ListView 中起作用
- java - Android 文件转字符串
d3 的新手,正在尝试开发一个力导向树,我们可以将 varios 数据集插入其中。我已经设法启动并运行了基本想法,但想使链接弯曲,以便我可以处理多个链接。我看过 http://bl.ocks.org/1153292我就是不明白。我得到的最近的结果是它在没有可见路径的情况下工作。这是我的直线代码,如果您有时间,我将不胜感激
感谢:
//Sets up the svg that holds the data structure and puts it in the div called mapBox
var svg = d3.select("div#mapBox.theMap").append("svg")
.attr("width", mapWidth)
.attr("height", mapHeight);
//Sets up the data structure and binds the data to it
var force = d3.layout.force()
.nodes(data.nodes)
.links(data.links)
.size([mapWidth, mapHeight])
.charge(-600)
.linkDistance(60)
.start();
//Draws the links and set up their styles
var link = svg.selectAll("link")
.data(data.links)
.enter().append("line")
.attr("class", "link")
.style("stroke", "#ccc")
//Creates nodes and attached "g" element to append other things to
var node = svg.selectAll(".node")
.data(data.nodes)
.enter().append("g")
.call(force.drag);
//Appends the cirdle to the "g" element and defines styles
node.append("circle")
.attr("r", function(d) { if (d.weight<1.1) {return 5} else {return d.weight*1.3+5 }})
.style("fill", "White")
.style("stroke-width", 3)
.style("stroke", function(d) { if (d.type==1) {return "#eda45e "} if(d.type==2) {return "#819e9a"}else {return "#c36256" }} ) // Node stroke colors
.on("mouseover", nodeMouseover)
on("mouseout", nodeMouseout)
.on("mousedown", nodeMousedown)
.call(force.drag);
//Appends text to the "g" element and defines styles
node.append("text")
.attr("class", "nodetext")
.attr("dx", 16)
.attr("dy", ".35em")
.attr("text-anchor", function(d) { if (d.type==1) {return "middle";} else {return "start";} })
.text(function(d) { return d.name })
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
});
最佳答案
Der,解决了。
改变
.enter().append("line")
到
.enter().append("path")
然后改变
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
到
link.attr("d", function(d) {
var dx = d.target.x - d.source.x,
dy = d.target.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);
return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + d.target.x + "," + d.target.y;
});
希望能帮助像我一样陷入困境的人
关于javascript - d3力导向树上的曲线,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13455510/
我是一名优秀的程序员,十分优秀!