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我目前在我的代码中这样做是为了处理可选项...
我做一个
fetchedResultController.performFetch(nil)
let results = fetchedResultController.fetchedObjects as [doesnotmatter]
// add all items to server that have no uid
for result in results {
let uid = result.valueForKey("uid") as String?
if uid == nil
{
let name = result.valueForKey("name") as String?
let trainingday = result.valueForKey("trainingdayRel") as Trainingdays?
if let trainingday = trainingday
{
let trainingUID = trainingday.valueForKey("uid") as String?
if let trainingUID = trainingUID
{
let urlstring = "http://XXXX/myGym/addTrainingday.php?apikey=XXXXXX&date=\(date)&appid=47334&exerciseUID=\(exerciseUID)"
let sUrl = urlstring.stringByAddingPercentEscapesUsingEncoding(NSASCIIStringEncoding)
let url = NSURL(string: sUrl!)
// save the received uid in our database
if let dictionary = Dictionary<String, AnyObject>.loadJSONFromWeb(url!)
{
trainingday.setValue(uid, forKey: "uid")
}
self.managedObjectContext!.save(nil)
}
}
}
}
实际上我还需要为每个“if let”语句添加一个“else”子句。这对我来说似乎是非常糟糕的代码!有没有更好的方法来做到这一点?
最佳答案
是的,使用 switch-case
和模式匹配你可以实现这个:
var x : SomeOptional?
var y : SomeOptional?
switch (x, y)
{
case (.Some(let x), .Some(let y)): doSomething() // x and y present
case (.None(let x), .Some(let y)): doSomethingElse() // x not present, but y
// And so on for the other combinations
default: break
}
看看这篇博文:Swift: Unwrapping Multiple Optionals
编辑(略微偏离主题且基于观点):这是我最喜欢的 Swift 功能之一。它还让您只需很少的代码即可实现 FSM,这非常棒。
关于swift - 进行可选链接的好方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28046614/
我正在尝试用 Swift 编写这段 JavaScript 代码:k_combinations 到目前为止,我在 Swift 中有这个: import Foundation import Cocoa e
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