javascript - 比较字符串并得到最终差异

Question

我有两个字符串。
字符串 A:“The quick brown fox”
字符串 B:“敏捷的棕色狐狸跳过懒惰的狗。”

字符串 B 将始终逐字包含字符串 A。永远不会有“敏捷的黑狐狸”或“敏捷而迅速的棕狐狸”。

如何得到“跳过懒狗”的“字符串 C”？

Answer 1

const A = "The quick brown fox"

const B = "The quick brown fox jumps over the lazy dog."

const diff = (diffMe, diffBy) => diffMe.split(diffBy).join('')

const C = diff(B, A)

console.log(C) // jumps over the lazy dog.