gpt4 book ai didi

ios - 如何在 INSendPaymentIntent 中选择电话号码

转载 作者:可可西里 更新时间:2023-11-01 01:28:12 30 4
gpt4 key购买 nike

在我的应用程序中,我需要使用用户的电话号码(而不是用户的联系人姓名)发送付款。因此,如果联系人中的用户有 2 个电话号码,则用户必须选择其中一个号码(如电话调用意图)。

在函数 func resolvePayee(forSendPayment intent: INSendPaymentIntent, with completion: @escaping (INPersonResolutionResult) -> Void) 中,我只看到用户的姓名,但没有电话号码。甚至 intent.payee.personH​​andle 总是 == nil

最佳答案

我使用了这个解决方法(当我显示他们时,只需在联系人姓名中添加数字)。以下是 resolvePayee 函数的完整代码:

func resolvePayee(forSendPayment intent: INSendPaymentIntent, with completion: @escaping (INPersonResolutionResult) -> Void) {

print("start resolving payee")

if let payee = intent.payee, payee.displayName.length > 0 {

// search proper phone number if we chose between these numbers before
var foundPhoneNumberInBuferNumbers: String? = nil
if let arrayOfSavedPhones = PaymentIntentHandler.resolvePayeeHelp_offeredPhoneNumbersFor1Contact {
for phone in arrayOfSavedPhones {
if payee.displayName.hasSuffix(phone) {
foundPhoneNumberInBuferNumbers = phone
break
}
}
if foundPhoneNumberInBuferNumbers == nil { // if we didn't manage to find this number that means that we have a new request for a new contact, so we don't need to remember number in buffer anymore
print("can't find phone number for \(payee.displayName), so we remove all buffer numbers = \(PaymentIntentHandler.resolvePayeeHelp_offeredPhoneNumbersFor1Contact)")
PaymentIntentHandler.resolvePayeeHelp_offeredPhoneNumbersFor1Contact = nil
}
}

let searchName = foundPhoneNumberInBuferNumbers != nil ? payee.displayName.replacingOccurrences(of: " " + foundPhoneNumberInBuferNumbers!, with: "") : payee.displayName

Singleton.sharedInstance.contactsService_getPhoneContacts(contactIdentifiresToFetch: nil, matchingName: searchName, showAlert: false, completionBlock: { (havePermission, customContactsMatchingName) in
if !havePermission { // user didn't grant permissions
print("unsupported because don't have permissions")
completion(INPersonResolutionResult.unsupported())
return
}

switch customContactsMatchingName.count {
case 2 ... Int.max: // user has to choose
let arrayOfPersons = customContactsMatchingName.map({ (phoneBookContact) -> INPerson in
return phoneBookContact.inSiriPerson()
})
print("disambiguation between several contacts")
completion(INPersonResolutionResult.disambiguation(with: arrayOfPersons))
case 1:
let contactCustom = customContactsMatchingName[0]
switch contactCustom.phoneNumbers.count {
case 0:
print("unsupported because don't have phone numbers")
completion(INPersonResolutionResult.unsupported())
case 1:
print("success")
completion(INPersonResolutionResult.success(with: contactCustom.inSiriPerson()))
case 2 ... Int.max:

print("now we have a uniq contact, but several phone numbers")

if foundPhoneNumberInBuferNumbers == nil { // we need user to choose between several phone numbers

var arrayOfStringNumbers = [String]()
var arrayOfPersonsToChoose = [INPerson]()
for phoneNumber in contactCustom.phoneNumbers {
let numberOnlyDigits = Singleton.sharedInstance.phone_getPhoneOnlyDigits(phoneNumber.number)
let formattedNumber = Singleton.sharedInstance.phone_getFormattedPhone("+" + numberOnlyDigits, allowLetters: false)
arrayOfStringNumbers.append(formattedNumber)
let personHandler = INPersonHandle(value: formattedNumber, type: .phoneNumber)
let person = INPerson(personHandle: personHandler, nameComponents: nil, displayName: payee.displayName + " " + formattedNumber, image: nil, contactIdentifier: contactCustom.id, customIdentifier: formattedNumber)
arrayOfPersonsToChoose.append(person)
}

PaymentIntentHandler.resolvePayeeHelp_offeredPhoneNumbersFor1Contact = arrayOfStringNumbers

print("disambiguation in one contact between several phones")
completion(INPersonResolutionResult.disambiguation(with: arrayOfPersonsToChoose))
}
else {

// found proper phone number
print("success after choosing bufer number")
let personHandle = INPersonHandle(value: foundPhoneNumberInBuferNumbers!, type: .phoneNumber)
let displayName = payee.displayName.replacingOccurrences(of: " " + foundPhoneNumberInBuferNumbers!, with: "")
completion(INPersonResolutionResult.success(with: INPerson(personHandle: personHandle, nameComponents: nil, displayName: displayName, image: nil, contactIdentifier: nil, customIdentifier: personHandle.value)))
}


default:
print("unsupported: can't happen")
completion(INPersonResolutionResult.unsupported())
}
case 0:
print("unsupported because can't find this contact in phonebook = \(searchName), contacts in buffer = \(PaymentIntentHandler.resolvePayeeHelp_offeredPhoneNumbersFor1Contact)")
completion(INPersonResolutionResult.unsupported())
default:
print("unsupported: can't happen")
completion(INPersonResolutionResult.unsupported())
}
})
}
else {
print("needsValue")
PaymentIntentHandler.resolvePayeeHelp_offeredPhoneNumbersFor1Contact = nil
completion(INPersonResolutionResult.needsValue())
}
}

关于ios - 如何在 INSendPaymentIntent 中选择电话号码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40205898/

30 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com