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javascript - promise : Execute something regardless of resolve/reject?

转载 作者:可可西里 更新时间:2023-11-01 01:24:17 24 4
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使用 Promises 设计模式,是否可以实现以下功能:

 var a, promise

if promise.resolve
a = promise.responsevalue;

if promise.reject
a = "failed"

AFTER resolution/rejection. Not ASYNC!!
send a somewhere, but not asynchronously. //Not a promise

我正在寻找的是类似于 finallytry - catch情况。

PS:我在 NodeJS 上使用 ES6 Promise polyfill

最佳答案

注意: finally现在是 JavaScript promise 的标准部分,所以你可以这样做:

thePromise.then(result => doSomething(result)
.catch(error => handleOrReportError(error))
.finally(() => doSomethingAfterFulfillmentOrRejection());

之前的回答 finally是标准的:

如果您从 catch 返回一个值, 那么你可以使用 then关于 catch 的结果.
thePromise.then(result => doSomething(result)
.catch(error => handleErrorAndReturnSomething(error))
.then(resultOrReturnFromCatch => /* ... */);

...但这意味着您将拒绝转换为履行(通过从 catch 返回某些内容,而不是抛出或返回被拒绝的 promise ),并依赖于这一事实。

如果您想要在不修改的情况下透明地传递履行/拒绝的东西,那么 ES2015(“ES6”) promise 中没有内置的东西可以做到这一点( 再次编辑:,现在有),但很容易写(这是在 ES2015 中,但我在下面有一个 ES5 翻译):
{
let worker = (p, f, done) => {
return p.constructor.resolve(f()).then(done, done);
};
Object.defineProperty(Promise.prototype, "finally", {
value(f) {
return this.then(
result => worker(this, f, () => result),
error => worker(this, f, () => { throw error; })
);
}
});
}

例子:

{
let worker = (p, f, done) => {
return p.constructor.resolve(f()).then(done, done);
};
Object.defineProperty(Promise.prototype, "finally", {
value(f) {
return this.then(
result => worker(this, f, () => result),
error => worker(this, f, () => { throw error; })
);
}
});
}
test("p1", Promise.resolve("good")).finally(
() => {
test("p2", Promise.reject("bad"));
}
);
function test(name, p) {
return p.then(
result => {
console.log(name, "initial fulfillment:", result);
return result;
},
error => {
console.log(name, "initial rejection; propagating it");
throw error;
}
)
.finally(() => {
console.log(name, "in finally");
})
.then(
result => {
console.log(name, "fulfilled:", result);
},
error => {
console.log(name, "rejected:", error);
}
);
}


对此有几点说明:
  • 注意 this.constructor 的使用所以我们调用resolve在任何类型的 promise (包括可能的子类)上创建了原始 promise ;这与 Promise.resolve 的方式一致和其他的工作,并且是支持子类 promise 的重要组成部分。
  • 以上是故意不是 包括 finally 的任何参数回调,并且没有指示 promise 是被履行还是被拒绝,为了与 finally 保持一致经典try-catch-finally结构体。但是,如果需要,可以轻松地将其中一些信息传递到回调中。
  • 同样,上面没有使用finally返回的值回调 除了 如果它是一个 promise ,它会在允许链继续之前等待 promise 解决。

  • 这是 ES5 的翻译:
    (function() {
    function worker(ctor, f, done) {
    return ctor.resolve(f()).then(done, done);
    }
    Object.defineProperty(Promise.prototype, "finally", {
    value: function(f) {
    var ctor = this.constructor;
    return this.then(
    function(result) {
    return worker(ctor, f, function() {
    return result;
    });
    },
    function(error) {
    return worker(ctor, f, function() {
    throw error;
    });
    }
    );
    }
    });
    })();

    例子:

    (function() {
    function worker(ctor, f, done) {
    return ctor.resolve(f()).then(done, done);
    }
    Object.defineProperty(Promise.prototype, "finally", {
    value: function(f) {
    var ctor = this.constructor;
    return this.then(
    function(result) {
    return worker(ctor, f, function() {
    return result;
    });
    },
    function(error) {
    return worker(ctor, f, function() {
    throw error;
    });
    }
    );
    }
    });
    })();

    test("p1", Promise.resolve("good")).finally(function() {
    test("p2", Promise.reject("bad"));
    });

    function test(name, p) {
    return p.then(
    function(result) {
    console.log(name, "initial fulfillment:", result);
    return result;
    },
    function(error) {
    console.log(name, "initial rejection; propagating it");
    throw error;
    }
    )
    .finally(function() {
    console.log(name, "in finally");
    })
    .then(
    function(result) {
    console.log(name, "fulfilled:", result);
    },
    function(error) {
    console.log(name, "rejected:", error);
    }
    );
    }


    我认为这是将此功能集成到 ES5 中的 Promise polyfill 中的最简单方法。

    或者,如果您更喜欢子类 Promise而不是修改它的原型(prototype):
    let PromiseX = (() => {
    let worker = (p, f, done) => {
    return p.constructor.resolve(f()).then(done, done);
    };
    class PromiseX extends Promise {
    finally(f) {
    return this.then(
    result => worker(this, f, () => result),
    error => worker(this, f, () => { throw error; })
    );
    }
    }
    PromiseX.resolve = Promise.resolve;
    PromiseX.reject = Promise.reject;

    return PromiseX;
    })();

    例子:

    let PromiseX = (() => {
    let worker = (p, f, done) => {
    return p.constructor.resolve(f()).then(done, done);
    };
    class PromiseX extends Promise {
    finally(f) {
    return this.then(
    result => worker(this, f, () => result),
    error => worker(this, f, () => { throw error; })
    );
    }
    }
    PromiseX.resolve = Promise.resolve;
    PromiseX.reject = Promise.reject;

    return PromiseX;
    })();

    test("p1", PromiseX.resolve("good")).finally(
    () => {
    test("p2", PromiseX.reject("bad"));
    }
    );
    function test(name, p) {
    return p.then(
    result => {
    console.log(name, "initial fulfillment:", result);
    return result;
    },
    error => {
    console.log(name, "initial rejection; propagating it");
    throw error;
    }
    )
    .finally(() => {
    console.log(name, "in finally");
    })
    .then(
    result => {
    console.log(name, "fulfilled:", result);
    },
    error => {
    console.log(name, "rejected:", error);
    }
    );
    }



    你说过你想在不扩展 Promise.prototype 的情况下这样做。或子类化。在 ES5 中,效用函数是 非常使用起来很尴尬,因为您必须将 promise 传递给它才能采取行动,这与正常的 promise 用法完全不符。在 ES2015 中,可以做一些更自然的事情,但调用起来仍然比修改原型(prototype)或子类化更痛苦:
    let always = (() => {
    let worker = (f, done) => {
    return Promise.resolve(f()).then(done, done);
    };
    return function always(f) {
    return [
    result => worker(f, () => result),
    error => worker(f, () => { throw error; })
    ];
    }
    })();

    用法:
    thePromise.then(...always(/*..your function..*/)).

    注意扩展运算符的使用(这就是为什么这在 ES5 中不起作用),所以 always可以为 then 提供两个参数.

    例子:

    let always = (() => {
    let worker = (f, done) => {
    return Promise.resolve(f()).then(done, done);
    };
    return function always(f) {
    return [
    result => worker(f, () => result),
    error => worker(f, () => { throw error; })
    ];
    }
    })();

    test("p1", Promise.resolve("good")).then(...always(
    () => {
    test("p2", Promise.reject("bad"));
    }
    ));
    function test(name, p) {
    return p.then(
    result => {
    console.log(name, "initial fulfillment:", result);
    return result;
    },
    error => {
    console.log(name, "initial rejection; propagating it");
    throw error;
    }
    )
    .then(...always(() => {
    console.log(name, "in finally");
    }))
    .then(
    result => {
    console.log(name, "fulfilled:", result);
    },
    error => {
    console.log(name, "rejected:", error);
    }
    );
    }



    您在评论中表达了对 finally 的担忧。不会等待 promise ;这是最后一个 always再举一个例子,延迟证明它确实如此:

    let always = (() => {
    let worker = (f, done) => {
    return Promise.resolve(f()).then(done, done);
    };
    return function always(f) {
    return [
    result => worker(f, () => result),
    error => worker(f, () => { throw error; })
    ];
    }
    })();

    test("p1", 500, false, "good").then(...always(
    () => {
    test("p2", 500, true, "bad");
    }
    ));

    function test(name, delay, fail, value) {
    // Make our test promise
    let p = new Promise((resolve, reject) => {
    console.log(name, `created with ${delay}ms delay before settling`);
    setTimeout(() => {
    if (fail) {
    console.log(name, "rejecting");
    reject(value);
    } else {
    console.log(name, "fulfilling");
    resolve(value);
    }
    }, delay);
    });

    // Use it
    return p.then(
    result => {
    console.log(name, "initial fulfillment:", result);
    return result;
    },
    error => {
    console.log(name, "initial rejection; propagating it");
    throw error;
    }
    )
    .then(...always(() => {
    console.log(name, "in finally");
    }))
    .then(
    result => {
    console.log(name, "fulfilled:", result);
    },
    error => {
    console.log(name, "rejected:", error);
    }
    );
    }

    关于javascript - promise : Execute something regardless of resolve/reject?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38830314/

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