php - 使用正则表达式获取标签内的引​​号

Question

你好。我试图在特定的开始-结束字符串中获取所有引号。假设我有这个字符串:

`Hello "world". [start]this is a "mark"[end]. It should work with [start]"several" "marks"[end]`

现在我希望 [start] .. [end] 中的每个 "都被 " 替换:

$string = 'Hello "world". [start]this is a "mark"[end]. It should work with [start]"several" "marks"[end]';
$regex = '/(?<=\[start])(.*?)(?=\[end])/';
$replace = '&quot;';

$string = preg_replace($regex,$replace,$string);

这匹配 [start] 和 [end] 之间的文本。但是我想匹配其中的 ":

//expected: Hello "world". [start]this is a "mark"[end]. It should work with [start]"several" "marks"[end]

有什么想法吗？

Answer 1

(?s)"(?=((?!\[start\]).)*\[end\])

Live demo

解释:

 (?s)                       DOT_ALL modifier
 "                          Literal "
 (?=                        Begin lookahead
      (                         # (1 start)
           (?! \[start\] )          Current position should not be followed by [start]
           .                        If yes then match
      )*                        # (1 end)
      \[end\]                   Until reaching [end]
 )                          End lookahead

PHP live demo