php - 交响服务

Question

请帮助我了解如何在我的服务中注入(inject) buzz http 包以从我的服务发送请求。

我的服务.yml

parameters:
    app_bundle.webUrl: https://url.com/
    app_bundle.Url: https://test.com
    app_bundle.token: rerwe9888rewrjjewrwj

services:
    app_bundle.send_message:
        class: AppBundle\Utils\SendMessage
        arguments: ["%app_bundle.webUrl%, %app_bundle.Url%, %app_bundle.token%, @buzz"]

我的 AppBundle\Utils\SendMessage

<?php

namespace AppBundle\Utils;

class SendMessage
{
    /**
     * SendMessage constructor.
     *
     * @param $webUrl
     * @param $Url
     * @param $token
     * @param Browser $buzz
     */
    public function __construct($webUrl, $Url, $token, Browser $buzz)
    {
        $this->webUrl = $webUrl;
        $this->Url = $Url;
        $this->token = $token;
        $this->buzz = $buzz;
    }

    /**
     * @param $action
     * @param null $data
     * @return mixed
     */
    private function sendRequest($action, $data = NULL)
    {
        $headers = array(
            'Content-Type' => 'application/json',
        );

        $response = $this->buzz->post($this->Url . $this->token . '/' . $action, $headers, json_encode($data));

        return $response;
    }
}

但这导致了错误:

request.CRITICAL: Uncaught PHP Exception Symfony\Component\Debug\Exception\FatalThrowableError: "Type error: Argument 4 passed to AppBundle\Utils\SendMessage::__construct() must be an instance of Buzz\Browser, none given, called in /app/var/cache/prod/appProdProjectContainer.php on line 270" at /app/src/AppBundle/Utils/SendMessage.php line 21 {"exception":"[object]

Answer 1

服务配置文件中定义的每个参数都必须用双引号括起来并用逗号分隔，如上例:

parameters:
    app_bundle.webUrl: https://url.com/
    app_bundle.Url: https://test.com
    app_bundle.token: rerwe9888rewrjjewrwj

services:
    app_bundle.send_message:
        class: AppBundle\Utils\SendMessage
        arguments: ["%app_bundle.webUrl%", "%app_bundle.Url%", "%app_bundle.token%", "@buzz"]

您只向构造函数提供了一个字符串参数:"%app_bundle.webUrl%, %app_bundle.Url%, %app_bundle.token%, @buzz"