php - SWIFT 和 PHP 与 JSON 交换

Question

iam 使用 swift 函数将 POST 查询发送到 php 脚本

func post_retJSON_inJSON(params : Dictionary<String, String>,tourl:String)
    {
        let myUrl = NSURL(string: tourl);
        let request = NSMutableURLRequest(URL:myUrl!);
        request.HTTPMethod = "POST";

        var err: NSError?
        request.HTTPBody =  NSJSONSerialization.dataWithJSONObject(params, options: nil, error: &err)

        request.addValue("application/json", forHTTPHeaderField: "Content-Type")
        request.addValue("application/json", forHTTPHeaderField: "Accept")


        let task = NSURLSession.sharedSession().dataTaskWithRequest(request)
            {
            data, response, error in

            if error != nil
            {
                println("error=\(error)")
                return
            }

            // You can print out response object
            println("response = \(response)")

            // Print out response body
            let responseString = NSString(data: data, encoding: NSUTF8StringEncoding)
            println("responseString = \(responseString)")

            //Let's convert response sent from a server side script to a NSDictionary object:

            var err: NSError?
            var myJSON = NSJSONSerialization.JSONObjectWithData(data, options: .MutableLeaves, error:&err) as? NSDictionary

            if let parseJSON = myJSON {
                // Now we can access value of First Name by its key
                var firstNameValue = parseJSON["firstName"] as? String
                println("firstNameValue: \(firstNameValue)")
            }

            UIApplication.sharedApplication().networkActivityIndicatorVisible = false

        }

        task.resume()
        UIApplication.sharedApplication().networkActivityIndicatorVisible = true
    }

用这个 php

$firstName= $_POST["firstName"];
$lastName = $_POST["lastName"]; 

$returnValue = array("firstName"=>$firstName, "lastName"=>$lastName);

// Send back request in JSON format
echo json_encode($returnValue);

然后我很快就有了回应

Optional({"firstName":null,"lastName":null})

我想我已经尝试了所有方法，但我无法获取 SWIFT 查询发送的 PHP 参数。请帮我弄清楚!!!

Answer 1

用这个 php 解决了，和 top 一样 swift

// Read request parameters
$postdata = json_decode(file_get_contents("php://input"),TRUE);

$firstName= $postdata["firstName"];
$lastName = $postdata["lastName"];
// Store values in an array
$returnValue = array("firstName"=>$firstName, "lastName"=>$lastName);

// Send back request in JSON format
echo json_encode($returnValue);