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php - 使用 php 不显示谷歌地图

转载 作者：可可西里 更新时间：2023-11-01 01:04:49 25 4
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我有一个 php 代码，它从数据库(测试)和表名 manu 获取位置信息，它是使用 wamp 中的 phpmyadmin 创建的，并使用标记在 map 上显示这些位置。感知经纬度值的位置详情。

已更新

<?
$dbname            ='test'; //Name of the database
$dbuser            =''; //Username for the db
$dbpass            =''; //Password for the db
$dbserver          ='localhost'; //Name of the mysql server

$dbcnx = mysql_connect ("$dbserver", "$dbuser", "$dbpass");
mysql_select_db("$dbname") or die(mysql_error());
 ?>


 <html>
 <head>
 <meta http-equiv="content-type" content="text/html; charset=utf-8"/>
 <style type="text/css">
  body { font: normal 10pt Helvetica, Arial; }
 #map { width: 350px; height: 300px; border: 0px; padding: 0px; }
 </style>
 <script src="http://maps.google.com/maps/api/js?v=3&sensor=false"        type="text/javascript" ></script>
 <script type="text/javascript" src="js/jquery.js"></script>
 <script type="text/javascript">

  var icon = new google.maps.MarkerImage("http://maps.google.com/mapfiles/ms/micons/blue.png",
  new google.maps.Size(32, 32), new google.maps.Point(0, 0),
  new google.maps.Point(16, 32));
  var center = null;
  var map = null;
  var currentPopup;
  var bounds = new google.maps.LatLngBounds();
  function addMarker(lat, lng, info) {
  var pt = new google.maps.LatLng(lat, lng);
  bounds.extend(pt);
  var marker = new google.maps.Marker({
  position: pt,
  icon: icon,
  map: map
  });
  var popup = new google.maps.InfoWindow({
  content: info,
  maxWidth: 300
  });

   google.maps.event.addListener(marker, "click", function() {
 if (currentPopup != null) {
   currentPopup.close();
  currentPopup = null;
  }
   popup.open(map, marker);
  currentPopup = popup;
 });
 google.maps.event.addListener(popup, "closeclick", function() {
 map.panTo(center);
  currentPopup = null;
 });
 }
 function initMap() {
 map = new google.maps.Map(document.getElementById("map"), {
 center: new google.maps.LatLng(0, 0),
  zoom: 14,
  mapTypeId: google.maps.MapTypeId.ROADMAP,
  mapTypeControl: false,
  mapTypeControlOptions: {
  style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
  },
  navigationControl: true,
  navigationControlOptions: {
  style: google.maps.NavigationControlStyle.SMALL
  }
   });


 $.getJSON('googlescript.php', function(items)
 {
 for (var i = 0; i < items.length; i++) 
 {
 (function(item) 
 {
 addMarker(item.lat, item.long, item.name + ' ' + item.desc);
 })(items[i]);
 }

 });


 center = bounds.getCenter();
  map.fitBounds(bounds);
 }

  </script>
  </head>
  <body onload="initMap()" style="margin:0px; border:0px; padding:0px;">
   <div id="map"></div>
  </body>
   </html>

googlescript.php 文件代码:

   <?php

   $dbname            ='test'; //Name of the database
   $dbuser            =''; //Username for the db
   $dbpass            =''; //Password for the db
   $dbserver          ='localhost'; //Name of the mysql server
   $tbl_name          ='manu';

   $dbcnx = mysql_connect ("$dbserver", "$dbuser", "$dbpass");
   mysql_select_db("$dbname") or die(mysql_error());

   $query = mysql_query("SELECT * FROM manu")or die(mysql_error());

   header('Content-Type: application/json');

   $rows = array();
   while ($row = mysql_fetch_array($query))
   {
    $rows[] = $row;
   }
  echo json_encode($rows);
  exit;
   ?>

最佳答案

HTML 页面

body onload="initMap()" //you forget to close it.<br/>
div id="map"

在 html 文件中进行了以下更改。

script src="http://maps.google.com/maps/api/js?v=3&sensor=false"    type="text/javascript"
script type="text/javascript" src="js/jquery.js"
script type="text/javascript">
    var icon = new google.maps.MarkerImage("http://maps.google.com/mapfiles/ms/micons/blue.png",
    new google.maps.Size(32, 32), new google.maps.Point(0, 0),
    new google.maps.Point(16, 32));
    var center = null;
    var map = null;
    var currentPopup;
    var bounds = new google.maps.LatLngBounds();
    function addMarker(lat, lng, info)
    {
        var pt = new google.maps.LatLng(lat, lng);
        bounds.extend(pt);
        var marker = new google.maps.Marker(
        {
            position: pt,
            icon: icon,
            map: map
        });
        var popup = new google.maps.InfoWindow(
        {
            content: info,
            maxWidth: 300
        });<p></p>

<pre><code>    google.maps.event.addListener(marker, "click", function()
    {
        if (currentPopup != null)
        {
            currentPopup.close();
            currentPopup = null;
        }
        popup.open(map, marker);
        currentPopup = popup;
    });
    google.maps.event.addListener(popup, "closeclick", function()
    {
        map.panTo(center);
        currentPopup = null;
    });
}
</code></pre>

<p>function initMap()
{
    map = new google.maps.Map(document.getElementById("map"), {
        center: new google.maps.LatLng(0, 0),
        zoom: 14,
        mapTypeId: google.maps.MapTypeId.ROADMAP,
        mapTypeControl: false,
        mapTypeControlOptions:
        {
            style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
        },
        navigationControl: true,
        navigationControlOptions:
        {
        style: google.maps.NavigationControlStyle.SMALL
        }
    });</p>

<pre><code>// getjson code goes here which is as below because i was unable to format it here so i wrote it downward.

center = bounds.getCenter();
map.fitBounds(bounds);
</code></pre>

<p>}
/script>
</p>


$.getJSON('googlescript.php', function(items)<br/>
{<br/>
for (var i = 0; i < items.length; i++) <br/>{<br/>
(function(item) <br/>{<br/>
addMarker(item.lat, item.long, item.name + ' ' + item.desc);<br/>
})(items[i]);<br/>
}<br/>
<br/> });

我用过$.getJSON('googlescript.php',所以你需要创建一个 googlescript.php文件并将下面的代码粘贴到其中。 


<code>$query = mysql_query("SELECT * FROM manu")or die(mysql_error());

header('Content-Type: application/json');

$rows = array();
while ($row = mysql_fetch_array($query))
{
    $rows[] = $row;
}
echo json_encode($rows);
exit;
</code>

?>

现在检查它的运行情况，我相信您会得到想要的结果。不要忘记更改 jquery 路径和更改数据库连接设置，请正确放置 jquery 路径。

关于php - 使用 php 不显示谷歌地图，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13720383/

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