php - Symfony2 自引用多对多关系

Question

我是 symfony2 的新手，我很难理解表格。

这个主题之前已经讨论过，但主要是关于关系方面的。我对表格以及如何管理关系的保存有疑问。一个用户的场景有很多用户 friend 。所以自引用多对多关系。

我正在使用 FOSUser Bundle 并且有一个友谊实体。这是用于创建实体的 YAML。

MH\FriendshipBundle\Entity\Friendship:
type: entity
table: mh_friendship
repositoryClass: MH\FriendshipBundle\Entity\FriendshipRepository
id:
    id:
        type: integer
        generator:
            strategy: AUTO
fields:
    requested_at:
        type: datetime
        gedmo:
            timestampable:
                on: create
    is_accepted:
        type: boolean
        nullable: true
    accepted_at:
        type: datetime
        nullable: true
manyToOne:
    user:
        targetEntity: MH\UserBundle\Entity\User
        inversedBy: user_friends
        joinColumn:
            name: user_id
            referencedColumnName: id
    friend:
        targetEntity: MH\UserBundle\Entity\User
        inversedBy: friend_users
        joinColumn:
            name: friend_id
            referencedColumnName: id
lifecycleCallbacks:
    prePersist:   [ ]
    postPersist:  [ ]
    preUpdate:    [ ]
    postUpdate:   [ ]


MH\UserBundle\Entity\User:
type:  entity
table: mh_user
repositoryClass: MH\UserBundle\Entity\UserRepository
id:
    id:
        type: integer
        generator:
            strategy: AUTO
fields:
    first_name:
        type: string
        length: 100
        nullable: true
    last_name:
        type: string
        length: 100
        nullable: true
    created_at:
        type: datetime
        gedmo:
            timestampable:
                on: create
    updated_at:
        type: datetime
        gedmo:
            timestampable:
                on: update
oneToMany:
    user_friends:
        targetEntity: MH\FriendshipBundle\Entity\Friendship
        mappedBy: user
        cascade: ["persist", "remove"]
    friend_users:
        targetEntity: MH\FriendshipBundle\Entity\Friendship
        mappedBy: friend
        cascade: ["persist", "remove"]
    friend_groups:
        targetEntity: MH\FriendshipBundle\Entity\FriendGroup
        mappedBy: owner
        cascade: ["persist", "remove"]
lifecycleCallbacks:
    prePersist:   [ ]
    postPersist:  [ ]
    preUpdate:    [ ]
    postUpdate:   [ ]

现在我有一个表单，它是通过友谊资源的 crud 生成器创建的，这就是我正在做的。

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('friend', 'entity', array(
                            'class' => 'UserBundle:User',
                            'property' => 'fullName',
                            'expanded' => true,
                            'multiple' => true,
                            'required' => false,
                    ))
    ;

}

它呈现了我可以选择并保存为“ friend ”的用户复选框列表。

我的问题是:

1. 保存时出现以下错误。

PHP Catchable fatal error: Argument 1 passed to MH\FriendshipBundle\Entity\Friendship::setFriend() must be an instance of MH\UserBundle\Entity\User, instance of Doctrine\Common\Collections\ArrayCollection given, called in /Users/mohammedhamad/Sites/sociabills/vendor/symfony/symfony/src/Symfony/Component/PropertyAccess/PropertyAccessor.php on line 345 and defined in /Users/mohammedhamad/Sites/sociabills/src/MH/FriendshipBundle/Entity/Friendship.php on line 155, referer: http://sociabills.local/friends/new

不确定如何确保将所选择的“ friend ”传递给需要集合的 setFriends 方法，而不是需要 User 对象的 setUser 方法。

1. 如何让表单列出除已登录用户之外的所有其他用户。不想一个人和自己交 friend 。

Answer 1

查看文档

/**
 * @ManyToMany(targetEntity="User", mappedBy="myFriends")
 **/
private $friendsWithMe;

/**
 * @ManyToMany(targetEntity="User", inversedBy="friendsWithMe")
 * @JoinTable(name="friends",
 *      joinColumns={@JoinColumn(name="user_id", referencedColumnName="id")},
 *      inverseJoinColumns={@JoinColumn(name="friend_user_id", referencedColumnName="id")}
 *      )
 **/
private $myFriends;

public function __construct() {
    $this->friendsWithMe = new \Doctrine\Common\Collections\ArrayCollection();
    $this->myFriends = new \Doctrine\Common\Collections\ArrayCollection();
}

// ...

注解的 YML 等价物是(请记住，我不习惯将 yml 用于实体映射，这未经过测试)

   manyToMany:
     myFriends:
       targetEntity: User
       inversedBy: friendsWithMe
       joinTable:
         name: friends
         joinColumns:
           user_id:
             referencedColumnName: id
         inverseJoinColumns:
           friends_user_id:
             referencedColumnName: id
     friendsWithMe:
       targetEntity: User
       mappedBy: myFriends

然后你可以在你的类中实现addMyFriend($friend)方法和removeMyFriend($friend)

public function addMyFriend($friend){

 $this->myFriends[] = $friend;

}

public function removeMyFriend($friend)
{
    $this->myFriends->removeElement($friend);
}

问题 2 由@Darragh 回答