php - 显示未定义索引 : password 的错误

Question

我是我的 session Controller ，我为验证电子邮件、登录名和更改密码编写代码，但出现错误

ErrorException in EloquentUserProvider.php line 116: Undefined index: password.

并从行代码中获取错误

if (!Auth::attempt($credentials_verifiy))

<?php
namespace App\Http\Controllers;

use Request;
use Response;
//----models--------
use App\Site;
use App\Jobs;


use Auth;
use DB;
use Validator;
use Redirect;

//use Illuminate\Support\Facades\Validator;
use Illuminate\Support\MessageBag;
class SessionController extends Controller {

    public function index(){
        return Redirect::to('login')->with('alert-success', 'test awrnning message.');
    }
    public function store()
    {
             $input = Request::only('username', 'email', 'password');
             $credentials = [
                 'username' => Request::get('username'),
                 'password' => Request::get('password')
             ];

            if (!Auth::attempt($credentials))
            {
                return Redirect::back()->with('alert-danger', 'Username or password do not match.');
            }
            else
            {
                $credentials_verifiy = [
                    'verified_email' => '1'
                ];
                if (!Auth::attempt($credentials_verifiy))
                {
                    return Redirect::back()->with('alert-danger', 'Please verify your email.');
                }
                else
                {
                    if(Auth::user()->last_login_at=='' || Auth::user()->last_login_at==null)
                    {
                        return redirect('/change_password');
                    }
                    else
                    {
                        return redirect('/tests');
                    }
                }
            }
    }
}

Answer 1

为了跳过这个异常你可以使用这行代码

array_get('password', $input);

如果数组 $input 没有索引 password 它不会抛出异常，它会返回 null，你可以让它返回你想要的: array_get('密码', $input, ' ');