ios - 使用 SwiftyJSON 获取 JSON 解析字典的键

Question

我想在这个 JSON 上获取“字典的键”(我就是这么叫的，不确定它是否正确)

{
  "People": {
    "People with nice hair": {
      "name": "Peter John",
      "age": 12,
      "books": [
        {
          "title": "Breaking Bad",
          "release": "2011"
        },
        {
          "title": "Twilight",
          "release": "2012"
        },
        {
          "title": "Gone Wild",
          "release": "2013"
        }
      ]
    },
    "People with jacket": {
      "name": "Jason Bourne",
      "age": 15,
      "books": [
        {
          "title": "Breaking Bad",
          "release": "2011"
        },
        {
          "title": "Twilight",
          "release": "2012"
        },
        {
          "title": "Gone Wild",
          "release": "2013"
        }
      ]
    }
  }
}

首先，我已经创建了我的 People 结构，它将用于从这些 JSON 进行映射。这是我的人员结构

struct People {
    var peopleLooks:String?
    var name:String?
    var books = [Book]()
}

这是我的 Book 结构

struct Book {
    var title:String?
    var release:String?
}

根据该 JSON，我使用 Alamofire 和 SwiftyJSON 创建了引擎，它们将通过完成处理程序在我的 Controller 中调用

Alamofire.request(request).responseJSON { response in
   if response.result.error == nil {
      let json = JSON(response.result.value!)
      success(json)
   }
}

这是我在 Controller 中所做的

Engine.instance.getPeople(request, success:(JSON?)->void),
   success:{ (json) in

   // getting all the json object
   let jsonRecieve = JSON((json?.dictionaryObject)!)

   // get list of people
   let peoples = jsonRecieve["People"]

   // from here, we try to map people into our struct that I don't know how.
}

我的问题是，如何将 jsonRecieve["People"] 中的 peoples 映射到我的结构中？我希望 "People with nice hair" 作为我的 People 结构上的 peopleLooks 的值。我认为 "People with nice hair" 是字典的关键字之类的东西，但我不知道如何获得它。

如有任何帮助，我们将不胜感激。谢谢!

Answer 1

例如，当您遍历字典时

for peeps in peoples

您可以访问 key

peeps.0

和值(value)

peeps.1