ios - 如何快速处理从多个社交登录帐户重定向回应用程序的登录？

Question

我正在制作一个允许用户从不同平台登录的应用程序，例如 google、Facebook、twitter 等。在 App 委托(delegate)中，我们必须为每个平台实现一个函数 application:openURL:options:。目前我的功能看起来像这样。

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

    // Todo handle based on the the arguments and return the bool value to be checked on iPHONE with facebook, google and twitter app
    let handled = FBSDKApplicationDelegate.sharedInstance().application(app, open: url, sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!, annotation: options[UIApplicationOpenURLOptionsKey.annotation])

    GIDSignIn.sharedInstance().handle(url, sourceApplication:options[UIApplicationOpenURLOptionsKey.sourceApplication] as? String, annotation: [:])

    Twitter.sharedInstance().application(app, open: url, options: options)

    return handled
}

如上所示，我返回的是 Facebook 的重定向句柄结果。 Google 和 twitter 也返回一个 bool 值。为上述函数返回 Facebook、google 和 twitter 的 handle bool 值的最安全和正确的方法是什么？

Answer 1

试试这个方法

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

     let facebookDidHandle = FBSDKApplicationDelegate.sharedInstance().application(app, open: url, sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!, annotation: options[UIApplicationOpenURLOptionsKey.annotation])

     let googleDidhandle = GIDSignIn.sharedInstance().handle(url, sourceApplication:options[UIApplicationOpenURLOptionsKey.sourceApplication] as? String, annotation: [:])

     let twitterDidHandle = Twitter.sharedInstance().application(app, open: url, options: options)


     return googleDidHandle || facebookDidHandle || twitterDidHandle
}