ios - 滑动删除多个选项

Question

当用户在聊天 View Controller 中滑动表格 View 单元格时，我想提供选项来阻止和删除该用户，或者只删除用户的聊天。有没有一种方法可以让滑动删除选项使这两个选项都可用？我应该在不同的页面上添加阻止用户选项，还是有办法在 commit editingStyle 函数中同时拥有这两者。

class Conversation {
var key:String
var sender:String
var recipient:String
var date:Date
var recentMessage:String
var seen:Bool

init(key:String, sender: String, recipient:String, date:Date, recentMessage:String, seen:Bool) {
    self.key = key
    self.sender = sender
    self.recipient = recipient
    self.date = date
    self.recentMessage = recentMessage
    self.seen = seen
}

// Returns the UID of the conversations partner
// i.e NOT the UID of the current user
var partner_uid:String {
    guard let uid = Auth.auth().currentUser?.uid else { return "" }
    if sender != uid {
        return sender
    }
    return recipient
}

func printAll() {
    print("key: \(key)")
    print("sender: \(sender)")

    print("recentMessage: \(recentMessage)")
}
 }

   class ChatsTableViewController:UIViewController, UITableViewDelegate, UITableViewDataSource {

var tableView:UITableView!

var conversations = [Conversation]()

override func viewDidLoad() {
    super.viewDidLoad()

    tableView = UITableView(frame: view.bounds)
    let nib = UINib(nibName: "ChatTableViewCell", bundle: nil)
    tableView.register(nib, forCellReuseIdentifier: "chatCell")
    tableView.delegate = self
    tableView.dataSource = self
    tableView.reloadData()

    title = "CHAT"
    view.addSubview(tableView)
}
func tableView(_ tableView: UITableView, commit editingStyle: UITableViewCellEditingStyle, forRowAt indexPath: IndexPath) {
    if editingStyle == .delete {
        let cell = tableView.cellForRow(at: indexPath) as! ChatTableViewCell
        let name = cell.usernameLabel.text!

        let actionSheet = UIAlertController(title: "Block conversation with \(name)?", message: "Further messages from \(name) will be muted.", preferredStyle: .alert)

        let cancelActionButton: UIAlertAction = UIAlertAction(title: "Cancel", style: .cancel) { action -> Void in }



        actionSheet.addAction(cancelActionButton)

        let deleteActionButton: UIAlertAction = UIAlertAction(title: "Block", style: .destructive)
        { action -> Void in
            self.muteConversation(self.conversations[indexPath.row])
        }

        let deleteOnlyButton: UIAlertAction = UIAlertAction(title: "Only Delete", style: .destructive)
        { action -> Void in


            print("only delete selected ")
        }

        actionSheet.addAction(deleteActionButton)
        actionSheet.addAction(deleteOnlyButton)
        self.present(actionSheet, animated: true, completion: nil)
    }
}

func muteConversation(_ conversation:Conversation) {
    guard let user = Auth.auth().currentUser else { return }
    let ref = Database.database().reference()

    let obj = [
        "social/blocked/\(user.uid)/\(conversation.partner_uid)" : true,
        "social/blockedBy/\(conversation.partner_uid)/\(user.uid)" : true,
        "conversations/users/\(user.uid)/\(conversation.partner_uid)/muted": true
    ] as [String:Any]
    print("OBBJ: \(obj)")
    ref.updateChildValues(obj, withCompletionBlock: { error, ref in
        if error != nil {
            let alert = UIAlertController(title: "Error deleting conversation!", message: nil, preferredStyle: .alert)
            alert.addAction(UIAlertAction(title: "Okay", style: .default, handler: nil))
        } else {
            let alert = UIAlertController(title: "Conversation blocked!", message: nil, preferredStyle: .alert)
            alert.addAction(UIAlertAction(title: "Okay", style: .default, handler: nil))
        }
    })
}

Answer 1

尝试此代码并将 Action1 和 Action2 替换为您喜欢的操作。

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {
let action1 = UITableViewRowAction(style: .default, title: "Action1", handler: {
    (action, indexPath) in
    print("Action1")
})
action1.backgroundColor = UIColor.lightGray
let action2 = UITableViewRowAction(style: .default, title: "Action2", handler: {
    (action, indexPath) in
    print("Action2")
})
return [action1, action2]
}