php - 肯定是一个愚蠢的错误，但我看不到

Question

我有一个表格(大大简化):

<form action='http://example.com/' method='post' name='event_form'>
  <input type='text' name='foo' value='3'/>
  <input type='submit' name='event_submit' value='Edit'/>
</form>

我有一个类“EventForm”来处理表单。主要方法 process() 如下所示:

public function process($submitname=false){
    $success=false;
    if ($submitname && isset($_POST[$submitname])){ //PROBLEM:  isset($_POST[$submitname] is always FALSE for some reason
        if($success=$this->ruler->validate()){//check that dependancies are honoured and data types are correct
            if($success=$this->map_fields()){//divide input data into Event, Schedule_Element and Temporal_Expression(s)
                $success=$this->eventholder->save();
            }
        }
    } else {//get the record from the db based on event_id or schedule_element_id
        foreach($this->gets as $var){//list of acceptable $_GET keys
            if(isset($_GET[$var])){
                if($success= $this->__set($var,$_GET[$var])) break;
            }
        }
    }
    $this->action=(empty($this->eventholder->event_id))? ADD : EDIT;
    return $success;
}

提交表单时，会发生这种情况:$form->process('event_submit'); 但出于某种原因，isset($_POST['event_submit']) 的计算结果始终为 FALSE。谁能看出原因？

预计到达时间:在完成建议后，JQuery.validate() 似乎对表单提交产生了意想不到的影响。除提交按钮外，所有字段均已提交。这似乎是这个 JQuery 的错误:

$("form[name='event_form']").validate({
    submitHandler: function(form) {
        form.submit();
    }
}};

关于如何确保发送提交按钮值有任何想法吗？

Answer 1

将您的 JQuery 更改为:

$("form[name='event_form']").validate({
    submitHandler: function(form) {
        $("form[name='event_form'] input[name='event_submit']").click()
    }
}};