php - 无法从 php 中的 $_FILES 获取多个上传的文件

Question

我无法从 $_FILES 检索我的 php 代码中的多个文件。这是输入表单:

<form enctype="multipart/form-data" action="file-upload.php" method="POST">
  Upload the several files:<input type="file" multiple="multiple" name="uploaded" id="id_upload" />
  <input type="submit" value="Upload" />
</form>

这是来自 file-upload.php 的 php 代码:

 // first let's find out how many files were uploaded..
 $numUploadedfiles = count($_FILES['uploaded']);
 $num_FILES = count($_FILES); 
        // BOTH COUNTS ARE 5.  I SELECT 7 FILE NAMES FOR UPLOADING THOUGH.


 echo "<br>" . "The number of uploaded files is == " . $numUploadedfiles;
 echo "<br>" . "Here is the name of _FILES['uploaded']: " . $_FILES['uploaded'];
     // THE NAME REPORTED IS 'array' AND THE COUNT IS 5..


 echo "<br>" . "The count size of _FILES is == " . $num_FILES;
 echo "<br>" . "Here is the name of _FILES => " . $_FILES;
       // HERE ALSO, THE NAME REPORTED IS 'array' AND THE COUNT IS 5.


 echo "<br>file temp_name " . $i . " is: " . $_FILES['uploaded']['tmp_name'];
 echo "<br>file name " . $i . " is: " . $_FILES['uploaded']['name'];
        // THE NAME REPORTED HERE IS THE FILENAME OF LAST OF THE 7 FILES I UPLOADED (not sure why.)


 echo "<br>" . "Here are the filenames: ";
 for($i = 0; $i < $numUploadedfiles; $i++)
 {
    echo "<br>filename " . $i . " is: " . $_FILES['uploaded'][$i];
 }
 exit();

当我运行它时发生的事情是，当“for”循环开始时，一条错误消息指出数组 _FILES['uploaded'][$i] 中的 $i 索引无效。

这是为什么呢？我需要获取这 7 个文件名并能够将它们保存在服务器上。我怎样才能:

1) 获得文件数量的准确“计数”？当我上传 7 个文件时，上面的代码计数为 5

2) 如何在“for”循环中正确索引 _FILES 数组？ PHP 告诉我 $i 值 0、1、2、3.... 无效。

(附:我正在使用我在 Retrieving file names out of a multi-file upload control with javascript 看到的启用多个文件上传的示例中的 input type="file"multiple="multiple"name="uploaded"id="id_upload"代码)

Answer 1

你的名字应该是数组:

<input type="file" name="uploaded[]" id="id_upload" />