php - 结合数组和连接值？

Question

解释起来有点复杂，所以这里有一个简单的具体例子:

数组 1:

Array
(
    [4] => bim
    [5] => pow
    [6] => foo 
)

数组 2:

Array
    (
        [n] => Array
            (
                [0] => 1
            )

        [m] => Array
            (
                [0] => 1
                [1] => 2
            )

        [l] => Array
            (
                [0] => 1
                [1] => 4
                [2] => 64
            )

我需要输出一个数组 3 ，

预期数组:

Array
        (
            [bim] => n-1
            [pow] => Array
                (
                    [0] => m-1
                    [1] => m-2
                )

            [foo] => Array
                (
                    [0] => l-1
                    [1] => l-4
                    [2] => l-64
                )

预期的最终回显输出:

bim n-1, pow m-1 m-2,foo l-1 l-4 l-64,

我试过了，但看起来很可惜:

foreach($array2 as $k1 =>$v1){

            foreach($array2[$k1] as $k => $v){
            $k[] =  $k1.'_'.$v);
             }



foreach($array1 as $res =>$val){

            $val = $array2;

            }

感谢您的帮助，杰斯

Answer 1

接受挑战

<?php

$a = array(
    4 => 'bim', 
    5 => 'pow', 
    6 => 'foo',
);
$b = array(
    'n' => array(1),
    'm' => array(1, 2),
    'l' => array(1, 4, 64),
);

$len = count($a);
$result = array();

$aVals = array_values($a);
$bKeys = array_keys($b);
$bVals = array_values($b);

for ($i = 0; $i < $len; $i++) {
    $combined = array();
    $key = $aVals[$i];
    $prefix = $bKeys[$i];
    $items = $bVals[$i];

    foreach ($items as $item) {
        $combined[] = sprintf('%s-%d', $prefix, $item);
    };

    if (count($combined) === 1) {
        $combined = $combined[0];
    }

    $result[$key] = $combined;
}

var_dump($result);

?>