swift - 在 swift 3 中创建复杂的 NSCompoundPredicate

Question

我想在 swift 3 中创建一个复杂的 NSCompoundPredicate，但是，我不知道该怎么做。

假设我有 5 个谓词 (p1,p2,p3,p4,p5)。我想实现以下条件:

compound1 = (p1 AND p2 AND p3) // NSCompoundPredicate(type: .and, 
                              //subpredicates: predicates)
compound2 = (p4 AND p5) // NSCompoundPredicate(type: .and, 
                       //subpredicates: predicates)
compound3 = (compound1 OR compound2) // problem is here

fetchRequest.predicate = compound3

NSCompoundPredicate 因为它的第二个参数获取它不需要的 NSPredicate 数组。什么是最佳解决方案？

Answer 1

NSCompoundPredicate 继承自 NSPredicate，因此你可以传递在第一步中创建的复合谓词作为另一个复合谓词的子谓词:

let compound1 = NSCompoundPredicate(type: .and, subpredicates: [p1, p2, p3])
let compound2 = NSCompoundPredicate(type: .and, subpredicates: [p4, p5])
let compound3 = NSCompoundPredicate(type: .or, subpredicates: [compound1, compound2])

fetchRequest.predicate = compound3