php - 使用 php 过滤 JSON 数据

Question

我正在尝试遍历这个 json 文件并过滤掉不需要的元素我想拆分结果所以我有一个客户列表或一个供应商列表json 文件:

{
  "$descriptor": "Test",
  "$resources": [
    {
      "$uuid": "281d393c-7c32-4640-aca2-c286f6467bb1",
      "$descriptor": "",
      "customerSupplierFlag": "Customer"
    },
    {
      "$uuid": "87a132a9-95d3-47fd-8667-77cca9c78436",
      "$descriptor": "",
      "customerSupplierFlag": "Customer"
    },
    {
      "$uuid": "8a75345c-73c7-4852-865c-f468c93c8306",
      "$descriptor": "",
      "customerSupplierFlag": "Supplier"
    },
    {
      "$uuid": "a2705e38-18d8-4669-a2fb-f18a87cd1cc6",
      "$descriptor": "",
      "customerSupplierFlag": "Supplier"
    }
  ]
}

例如

    {
      "$uuid": "281d393c-7c32-4640-aca2-c286f6467bb1",
      "$descriptor": "",
      "customerSupplierFlag": "Customer"
    },
    {
      "$uuid": "87a132a9-95d3-47fd-8667-77cca9c78436",
      "$descriptor": "",
      "customerSupplierFlag": "Customer"
    },

我的 php 代码是

$array = json_decode($result, true);


for ($i = 0; $i < count($array['$resources']); $i++){
    foreach ($array['$resources'][$i]['customerSupplierFlag'][Customer] as $item)
    {
        // do what you want
        echo $item['customerSupplierFlag' ]. '<br>';
        echo $item['$uuid'] . '<br>';
    }
}

几天来我一直在努力解决这个问题，现在似乎正在阅读相同的文章，如果有任何建议，我们将不胜感激。

Answer 1

$data = file_get_contents('./your_json_data.txt');

$json = json_decode($data, 1);

$resources = $json['$resources'];

$suppliers = array();
$customers = array();

foreach ($resources as $rkey => $resource){

    if ($resource['customerSupplierFlag'] == 'Customer'){

        $customers[] = $resource;

    } else if ($resource['customerSupplierFlag'] == 'Supplier') {

        $suppliers[] = $resource;

    }

}

header('Content-Type: application/json');

echo json_encode($customers);
echo json_encode($suppliers);

die();