php - 在函数中使用 "use"？

Question

我正在尝试完成以下工作:

function flosoftdedicated_api_init() {
require_once 'resources/vendor/autoload.php';
use \Ovh\Common\Ovh;

....

$ovh = new Ovh($config);
return $ovh;
}

function flosoftdedicated_ClientArea($params) {
global $ovh;

$ovh = flosoftdedicated_api_init();
....
}

但是我得到了错误:

Parse error: syntax error, unexpected T_USE in ..../flosoftdedicated.php on line 35 Line 35 being the use statement.

函数中不能使用命名空间吗？我需要分配相同的命名空间吗？

Answer 1

这是因为您不能在函数内声明它。来自 PHP: Using Namespaces :

The use keyword must be declared in the outermost scope of a file (the global scope) or inside namespace declarations. This is because the importing is done at compile time and not runtime, so it cannot be block scoped.

您必须将它移到任何函数或类之外。