php - 处理 PHP 和 HTML 逻辑的更好解决方案

Question

想知道您是否可以向我展示一种处理此逻辑的更好方法？我写了这篇文章，对此感到非常羞愧。你能告诉我这个逻辑的更好优化版本吗？

P.S $result["item"];返回一个整数。

$type = $result["item"];
switch ($type){
case "1":
$type_output = '    
<option value="1" selected>Cash</option>
<option value="2">Cheque</option>
<option value="3">Debit Card</option>
<option value="4">Credit Card</option>';
break;

case "2":
$type_output = '    
<option value="1">Cash</option>
<option value="2" selected>Cheque</option>
<option value="3">Debit Card</option>
<option value="4">Credit Card</option>';
break;

case "3":
$type_output = '    
<option value="1">Cash</option>
<option value="2">Cheque</option>
<option value="3" selected>Debit Card</option>
<option value="4">Credit Card</option>';
break;

case "4":
$type_output = '    
<option value="1">Cash</option>
<option value="2">Cheque</option>
<option value="3">Debit Card</option>
<option value="4" selected>Credit Card</option>';
break;
}

html

<td>
<select style="width:200px;" name="payment_type">
<option value=""> </option>
'.$type_output.'
</select>
</td>

谢谢

Answer 1

我会使用这种方法

$type = $result["item"];
$type_output = "";

$options =array(
    "1"=>"cash",
    "2"=>"Cheque",
    "3"=>"Debit Card",
    "4"=>"Credit Card",
);

foreach($options as $value=>$text) {
    $type_output .= "<option value=\"$value\"".($type==$value? " selected" : "").">$text</option>\n";
}