php - 在 PHP 中合并 2 个对象数组

Question

如何合并数组 1 和 2？

array1

Array
(
    [0] => stdClass Object
    (
        [name] => bob
        [id] => 84569354306
        [contacts] => Array
        (
            [0] => none
        )
    )
    [1] => stdClass Object
    (
        [name] => jill
        [id] => 456745742
        [contacts] => Array
        (
            [0] => none
        )
    )
)

array2

Array
(
    [0] => stdClass Object
    (
        [name] => bob
        [id] => 84569354306
        [pid] => 1
        [lang] => eng;
        [location] =>
    )
    [1] => stdClass Object
    (
        [name] => jill
        [id] => 456745742
        [pid] => 2
        [lang] => eng;
        [location] =>
    )
)

结果数组:

Array
(
    [0] => stdClass Object
    (
        [name] => bob
        [id] => 84569354306
        [pid] => 1
        [lang] => eng;
        [location] =>
        [contacts] => Array
        (
            [0] => none
        )
    )
    [1] => stdClass Object
    (
        [name] => jill
        [id] => 456745742
        [pid] => 2
        [lang] => eng;
        [location] =>
        [contacts] => Array
        (
            [0] => none
        )
    )
)

我试过 array_merge()，它似乎在数组中将对象彼此相邻添加，而不是合并对象。

我很确定 this question 与我需要的类似，但我在使用简单的 foreach 循环时遇到困难。

Answer 1

您可以将两个对象转换为数组，然后重新转换回一个对象。一般语法是:

$merged = (object)array_merge_recursive((array)$firstObj, (array)$secondObj);
                              ^
                              | note the recursive in your case

此外，如果您正在使用类似的对象，也许您应该坚持使用数组。对对象做那样的事情几乎没有意义

有多个项目

如果您有多个项目，您只需将我的脚本包装在一个循环中:

function myCustomMerge($array1, $array2) {
   assert('count($array1) == count($array2)');
   $result = array();
   foreach($array1 as $k=>$v) {
    $item = array_merge_recursive((array)$array1[$k], (array)$array2[$k]);
    $result[]=$item; // use (object)$item if you need objects
   }
   return $result;
}

没有类型转换的解决方案

如果您不想在数组和对象之间来回转换，您可以使用 get_object_vars():

$obj2props = get_object_vars($obj2);
foreach ($obj2props as $prop => $value) {
    $obj1->$prop = $value;
}
return $obj;