parse-platform - 使用 Swift 1.2 注册解析用户

Question

我按照描述使用 Parse.com 的注册功能 here .这是我的代码:

 user.signUpInBackgroundWithBlock {
    (succeeded: Bool!, error: NSError!) -> Void in
    if error == nil {
      // Hooray! Let them use the app now.
    } else {
      let errorString = error.userInfo["error"] as NSString
      // Show the errorString somewhere and let the user try again.
    }
  }
}

不幸的是，我已经将我的项目从 swift 1.1 更新到 swift 1.2 并得到以下编译器错误:

Function signature '(Bool!, NSError!)->void is not compatible with excepted type '@objc_block (Bool,NSError!)->Void'

它在下面一行:

user.signUpInBackgroundWithBlock {
        (succeeded: Bool!, error: NSError!) -> Void in

有谁知道我该如何解决这个问题？谢谢!

Answer 1

您的成功变量是一个“Bool!”但该 block 返回的是“Bool”(没有感叹号)。

解决方案是:

user.signUpInBackgroundWithBlock {
    (succeeded: Bool, error: NSError!) -> Void in
    if error == nil {
      // Hooray! Let them use the app now.
    } else {
      let errorString = error.userInfo["error"] as NSString
      // Show the errorString somewhere and let the user try again.
    }
  }
}

查看更多关于选项的信息 go to the apple doc