ios - openURL 和 canOpenURL 之间的区别

Question

我需要在 safari 浏览器中打开一个链接，但我有疑问，我应该使用哪种方法？ openURL/open 或 canOpenURL。谁能帮我解释一下这两种功能之间的实际区别是什么？

 if #available(iOS 10.0, *) {
       UIApplication.shared.open(URL(string: urlStr)!, options: [:], completionHandler: nil)
       UIApplication.shared.canOpenURL(URL(string: urlStr)!)

    } else {
        UIApplication.shared.openURL(URL(string: urlStr)!) //introduced: 2.0, deprecated: 10.0,

        UIApplication.shared.canOpenURL(URL(string: urlStr)!) // available(iOS 3.0, *)
    }

Answer 1

canOpenURL(_:)

返回一个 bool 值，指示 URL 的方案是否可以由安装在设备上的某些应用程序处理。

openURL(_:)

尝试在指定的 URL 打开资源。

openURL(_:) 已弃用 - iOS 10.0

改用open(_:options:completionHandler:) 方法。示例:

if UIApplication.shared.canOpenURL(url) {
    if #available(iOS 10.0, *) {
         UIApplication.shared.open(url, options: [:], completionHandler: { (success) in

         })
    } else {
         UIApplication.shared.openURL(url)
    }
}

If your app is linked on or after iOS 9.0, you must declare the URL schemes you pass to this method by adding the LSApplicationQueriesSchemes key to your app's Info.plist file. This method always returns false for undeclared schemes, whether or not an appropriate app is installed.