php - fatal error : Call to undefined function tally()

Question

我有以下用于 php 测验的代码。

if(isset($_POST['submit'])) {

    //Check to make sure that the name field is not empty
        if(($_POST['q_1'] == '') ||  ($_POST['q_2'] == '') || ($_POST['q_3'] == '') || ($_POST['q_4'] == '') || ($_POST['q_5'] == '')) {
            $nameError = 'Please choose an option';
            $hasError = true;
        }
        else {
                for ($i=1; $i<=$types; $i+=1)
                    {
                        $nowval[$i] = 0;
                    }
                for ($i=1; $i<=$questions; $i+=1)
                    {
                        $qvar = "q_$i";
                        //echo $qvar;
                        tally($_POST[$qvar]);// LINE THAT CAUSES ERROR
                    }
                $dominant = 1;
                $domval = $nowval[1];
                for ($i=2; $i<=$types; $i+=1)
                    {
                        if ($domval < $nowval[$i])
                            {
                                $dominant = $i;
                                $domval = $nowval[$i];
                            }
                    }
                function tally ($question) // TALLY FUNCTION
                    {   
                        global $nowval;
                        $nowval[$question]++;
                    }
                if (is_file("$quiz.rsl"))
                    {
                        $fp = fopen("$quiz.rsl", 'r');
                        $line = fgets($fp, 1024);
                        fclose($fp);
                        $people = explode("|", $line);
                        $people[$dominant-1] += 1;
                        $timestaken = 0;
                        foreach($people as $tally)
                            {
                                settype($tally, 'integer');
                                $timestaken += $tally;
                            }
                        $fp = fopen("$quiz.rsl", 'w');
                        for($i=0; $i<$types; $i++)
                            {
                                fwrite($fp, $people[$i]."|");
                            }
                        fclose($fp);
                    }
                else
                    {
                        for($i=0; $i<$types; $i++)
                            {
                                $people[] = 0;
                            }
                        $people[$dominant-1] += 1;
                        $timestaken = 1;
                        $fp = fopen("$quiz.rsl", 'w');
                        for($i=0; $i<$types; $i++)
                            {
                                fwrite($fp, $people[$i]."|");
                            }
                        fclose($fp);
                    }
                $percentage = ($people[$dominant-1] / $timestaken) * 100;
                $dec=2;
                $format="%.$dec" . "f";  
                $number=sprintf($format,$percentage);
                $percentage=strtok($number,".");
                $dc=strtok(".");   
                if ($dec!=0) 
                    { 
                        $percentage = "$percentage" . ".$dc";
                    } 

                $emailSent = true;
    }//else
}//main if

当我POST 表单数据到一个不同的文件时，即，如果上面的代码写在一个单独的文件中，它一切正常。

但是当我POST 表单数据到页面本身时，我得到了

Fatal error: Call to undefined function tally()

我不明白这个问题的根本原因。

当我尝试使用

                $this->tally($_POST[$qvar]);

我收到以下错误。

Fatal error: Using $this when not in object context

Answer 1

发生这种情况是因为您在尝试调用函数后才声明该函数:

tally($_POST[$qvar]);// LINE THAT CAUSES ERROR

function tally ($question) // TALLY FUNCTION DECLARATION COMES LATER

我会把其中一个放在前面if(isset($_POST['submit'])) { 或作为里面的第一件事。

   if (!function_exists('tally')) {
   function tally ($question) // TALLY FUNCTION
       {   
            global $nowval;
            $nowval[$question]++;
       }   
  }

$this->tally 不会工作，因为它不是一个对象，你只是在 decrating 一个函数。