ios - 错误 : Cannot subscript a value of type 'inout [Agenda]' (aka 'inout Array' )

Question

我正在制作一个应用程序，当您按下一个表示紧急的按钮时，会有一个标签显示“紧急”。就在我实现与按钮的用户交互之前，我有一个数组(如下所示)，其中一些对象具有 urgent = true，但有些对象具有 urgent = false，所以我可以从我的代码开始。

MainTableViewController.swift中的数组:

var content:[Agenda] = [
    Agenda(subject: "Read this article", deadline: "1-2 days", urgent: false),
    Agenda(subject: "Respond to this email", deadline: "ASAP", urgent: true),
    Agenda(subject: "Add this to diary", deadline: "When at home", urgent: true),
    Agenda(subject: "Listen to this song", deadline: "When finished working", urgent: false),
    Agenda(subject: "Check out this holiday destination", deadline: "At the weekend", urgent: false),
    Agenda(subject: "Download this podcast", deadline: "1-4 days", urgent: false),
    Agenda(subject: "Update notes", deadline: "When at home", urgent: true)
]

然后，我有一个名为 Agenda.swift 的类，我在其中声明了 subject、deadline 和 urgent.

这是我是否显示“紧急”的代码:

if content[indexPath.row].urgent = true {
        cell.urgentLabel.text = "URGENT"
    } else {
        cell.urgentLabel.text = ""
    }

在第一行，我收到以下错误:

Cannot subscript a value of type 'inout [Agenda]' (aka 'inout Array')

Answer 1

这是经典的赋值运算符 (=) 与等式运算符 (==) 的混淆。