php - 如何获取一个类的所有公共(public)属性作为json？

Question

考虑以下示例:

<?php

class p{
    public $name = 'jimmy';
    public $sex = 'male';
    private $age = 31;
    // there should be more unknow properties here ..

    function test(){
        echo $this->name;
    }

    function get_p_as_json(){
        // how can i get json of this class which contains only public properties ?
        // {"name":"jimmy","sex":"male"}
    }

}

$p = new p();
$json = $p->get_p_as_json();
echo $json;

问题:如何获取一个类的所有public属性作为JSON？

Answer 1

您只需创建另一个类 q 扩展自 p。然后代码如下所示:

class p {
    public $name = 'jimmy';
    public $sex = 'male';
    private $age = 31;
    // there should be more unknown properties here ..

    function test(){
        echo $this->name;
    }
}

class q extends p {
    function get_p_as_json($p) {
        return json_encode(get_object_vars($p));
    }
}
$q  =   new q();
$p  =   new p();
$json   =   $q->get_p_as_json($p);
echo $json;