php - Ajax Response Json 在表格或div数组中打印结果

Question

我有一个对 php 文件的 ajax 调用，该文件将数组编码为 json 数组/对象。我想做的是将 json 响应打印成表格格式或数组 分区的。我坚持如何处理 ajax 成功的响应。这是我的 ajax..

<script>
    $(document).ready(function(){
        $("#adapter").keyup(function()
        {
            var adapter = $(this).val();
            var dataString = 'searchword='+ adapter +'&format=json' ;
            if(adapter=='' || adapter < 2 )
            {
                $("#display3").hide('');        
            }
            else
            {
                $.ajax({
                    type: "POST",
                    url: "ajax/phpfile",
                    data: dataString,
                    cache: false,
                    success: function(data) 
                    {
                        var myObj = data;
                        ///NOT how to print the result and decode in html or php///
                    }
                });
            }return false; 
        });
    });
</script>

这是从服务器返回的 json 响应。我可以提醒整个 json 响应，所以我知道它在 ajax 端工作...

{"Result":[{"ptos":{"PTOMasterID":"1","PTOMasterPart":"828B-U6805-L1CX","PTOSeriesUniqueID":"22","PTOPrice":"2715.78","PTOSeries":"82","PTOMounting":"8B","PTOTransmission":"U68","PTOSpeed":"05","PTOShifter":"L","PTOAssemblyID":"1","PTOShaftID":"C","PTOSpecialFeature":"X","PTODate":"2011-11-30 17:28:10"}},{"ptos":{"PTOMasterID":"2","PTOMasterPart":"828B-U6805-L3CX","PTOSeriesUniqueID":"22","PTOPrice":"2715.78","PTOSeries":"82","PTOMounting":"8B","PTOTransmission":"U68","PTOSpeed":"05","PTOShifter":"L","PTOAssemblyID":"3","PTOShaftID":"C","PTOSpecialFeature":"X","PTODate":"2011-11-30 17:28:10"}]}

Answer 1

$(document).ready(function(){
    $("#adapter").keyup(function()
    {
        var adapter = $(this).val();
        var dataString = 'searchword='+ adapter +'&format=json' ;
        if(adapter=='' || adapter < 2 )
        {
            $("#display3").hide('');        
        }
        else
        {
            $.ajax({
                type: "POST",
                dataType: "json", //set this to json
                url: "ajax/phpfile",
                data: dataString,
                cache: false,
                success: function(data) 
                {
                    var myObj = data;
                    ///NOT how to print the result and decode in html or php///
                    console.log(myObj); //to see the object
                }
            });
        }return false; 
    });
});

或者你可以像这样使用 JSON2.js

JSON.parse(text, reviver)

JSON 2 GITHUB