php - CodeIgniter 参数没有传递给库？

Question

好的，我正在尝试将参数传递给我创建的用于扩展 CI_Form_validation 类的库的构造函数。无论如何，这是我从模型中传递的内容:

$this->load->library('MY_Form_validation', array('config' => '', 'post' => $this->input->post()));

然后是 MY_Form_validation 库:

private $post;

    public function __construct($params) {
        parent::__construct($params['config']);
        $this->post = $params['post'];
    }

但它说我没有传递任何东西。以下是错误消息:

Message: Missing argument 1 for MY_Form_validation::__construct(), called in H:\WD SmartWare.swstor\HALEY-HP\Source\DStable\stable\core\Loader.php on line 1099 and defined
Message: Undefined variable: params

编辑根据要求，全类:

class MY_Form_validation extends CI_Form_validation {
    private $post;

    public function __construct($params) {
        parent::__construct($params['config']);
        $this->post = $params['post'];
    }
}

Answer 1

您只需传递一个空数组而不是空字符串作为构造函数的第一个参数，该参数将发送给父级:

$this->load->library('MY_Form_validation', array('config' => array(), 'post' => $this->input->post()));

CI 表单验证库实际上是这样初始化配置参数的，这是来自 system/libraries/Form_validation.php 的构造函数:

public function __construct($rules = array())