php - Zend Framework 函数不是 Controller 中的操作

Question

在 Controller 中创建一个不是 Action 的函数是不好的做法吗？

例子:下面Controller中的createCookie函数

protected $translator;
protected $cookie;

public function __construct($translator, $cookie)
{
    $this->translator = $translator;
    $this->cookie = $cookie;
}

public function changeLanguageAction()
{
    $language = $this->params()->fromRoute('lang', 'en');
    $this->createCookie('xuage', $language, '/');
    $this->getResponse()->getHeaders()->addHeader($this->cookie);
    $this->redirect()->toRoute('home');
}

public function createCookie($name, $value, $path)
{
    $this->cookie->setName($name);
    $this->cookie->setValue($value);
    $this->cookie->setPath($path);
}

Answer 1

我建议创建一个 CookieService，并在此服务中使用公共(public)方法 createCookie。然后，您可以将此服务注入(inject)到您的 Controller 类中，并在您的操作中调用此方法，而不会用额外的 cookie 相关逻辑污染您的 Controller 类。

protected $translator;
protected $cookieService;

public function __construct($translator, CookieService $cookie)
{
    $this->translator = $translator;
    $this->cookieService = $cookieService;
}

public function changeLanguageAction()
{
    $language = $this->params()->fromRoute('lang', 'en');
    $this->cookieService->createCookie('xuage', $language, '/');
    $this->redirect()->toRoute('home');
}

将 cookie 添加到响应中也可以在此服务中完成。所以这一行将在您的 CookieService 中解决:

$this->getResponse()->getHeaders()->addHeader($this->cookie);