PHP用空格替换每个非字母数字字符

Question

我找了又找。我找不到解决方案。我有一个字符串，有点像这样:ABC_test 001-2.jpg

我也有这段代码:

$makeSpace = preg_replace("/[^a-zA-Z0-9\s]/", " ", $replaceUnder);

但是，这段代码不会替换下划线 (_)。其实这个变量的输出是:ABC

所以它一旦碰到下划线就会停止。我需要替换所有可能的非字母数字字符，包括下划线、星号、问号等等。我错过了什么？

感谢您的帮助。

编辑:

<?php
       //set images directory
        $directory = 'ui/images/customFabrication/';
        try {
            // create slideshow div to be manipulated by the above jquery function
            echo "<div class=\"slideLeft\"></div>";
                echo "<div class=\"sliderWindow\">";
                    echo "<ul id=\"slider\">";
            //iterate through the directory, get images, set the path and echo them in img tags.
            foreach ( new DirectoryIterator($directory) as $item ) {
                if ($item->isFile()) {
                    $path = $directory . "" . $item;
                    $class = substr($item, 0,-4); //removes file type from file name
                    //$replaceUnder = str_replace("_", "-", $class);
                    $makeDash = str_replace(" ", "-", $replaceUnder);

                    $replaceUnder = preg_replace("/[^a-zA-Z0-9\s]/", " ", $class);

                    //$makeSpace = preg_replace("/[^a-zA-Z0-9\s]/", "&nbsp;", $replaceUnder);
                    echo "<li><img rel=" . $replaceUnder . " class=" . $class . " src=\"/ui/js/timthumb.php?src=/" . $path . "&h=180&w=230&zc=1\" /></li>";
                }
            }
                    echo "</ul>";
                echo "</div>";
            echo "<div class=\"slideRight\"></div>";
        }
       //if directory is empty throw an exception.
        catch(Exception $exc) {
            echo 'the directory you chose seems to be empty';
        }
        ?>

Answer 1

我无法重现你的问题，对我来说输出的字符串是:

$replaceUnder = 'ABC_test 001-2.jpg';
$makeSpace = preg_replace("/[^a-zA-Z0-9\s]/", " ", $replaceUnder);
print_r($makeSpace);

# output:
# ABC test 001 2 jpg

.

调试你的代码

我查看了您粘贴的代码，发现了一些错误，这些错误可能相关，也可能不相关:

我在这一行收到一个错误，因为 replaceUnder 没有定义:

$makeDash = str_replace(" ", "-", $replaceUnder);

因为你注释掉了这一行:

//$replaceUnder = str_replace("_", "-", $class);

我猜你也想把它注释掉。根本不清楚您要做什么以及为什么要使用所有这些替换语句。如果您只是想用替换的所有符号来回显文件名，我就是这样做的，所有字母都被空格替换了:

<?php
//set images directory
$directory = './';
try {
    foreach ( new DirectoryIterator($directory) as $item ) {
        if ($item->isFile()) {
            $path = $directory . "" . $item;
            // remove ending/filetype - the other method doesn't support 4 letter file endings
            $name = basename($item);
            $fixedName = preg_replace("/[^a-zA-Z0-9\s]/", " ", $name);
            echo "Name: $fixedName\n";
        }
    }
            
}
//if directory is empty throw an exception.
catch(Exception $exc) {
    echo 'the directory you chose seems to be empty';
}
?>

我认为您的整个问题都源于变量的命名。考虑打开通知错误 - 如果您正在引用 undefined variable ，它们会通知您。