php - 想在php中发送和接收json数据

Question

根据应用程序要求，我正在尝试开发两个可以通过 Json 相互通信的 PHP。我尝试在线搜索但没有找到解决方案。

任何人都可以建议我正确的路径吗？

我在 mysql 数据库中有数据，转换后的数据将采用 json 格式，如下所示:(也在寻找通过 PHP-JSON 对象和数组获取此数据格式的代码。)

{ "user" : [   
             { "firstName" : "Vignesh",  
               "lastName"  : "Prajapati",
               "age"       : 23,
               "email"     : ["vignesh@gmail.com","vignesh@yahoo.com"],
               "subject"   : ["English","Gujarati", "Hindi"]
             }, 

             { "firstName" : "Vaibhav",  
               "lastName"  : "Prajapati",
               "age"       : 19,
               "email"     : ["vaibhav@gmail.com","vaibhav@yahoo.com","vaibhav@aol.com"],
               "subject"   : ["English","Spanish", "Chinese","Sanskrit"]
             }
           ]
} 

我的发送Json数据的Php代码:(send.php)

<?php

$data = '    { "user" : [   
                 { "firstName" : "Vignesh",  
                   "lastName"  : "Prajapati",
                   "age"       : 23,
                   "email"     : ["vignesh@gmail.com","vignesh@yahoo.com"],
                   "subject"   : ["English","Gujarati", "Hindi"]
                 }, 

                 { "firstName" : "Vaibhav",  
                   "lastName"  : "Prajapati",
                   "age"       : 19,
                   "email"     : ["vaibhav@gmail.com","vaibhav@yahoo.com","vaibhav@aol.com"],
                   "subject"   : ["English","Spanish", "Chinese","Sanskrit"]
                 }
               ]
    } ';

$url_send ="http://localhost/rec.php";
$str_data = json_encode($data);

function sendPostData($url, $post){
  $ch = curl_init($url);
  curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");  
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_POSTFIELDS,$post);
  curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
  $result = curl_exec($ch);
  curl_close($ch);  // Seems like good practice
  return $result;
}

echo " " . sendPostData($url_send, $str_data);

?>

我的接收Json数据的Php代码:(rec.php)

<?php

$json_input_data=json_decode(file_get_contents('php://input'),TRUE);

echo $json_input_data;


?>

Answer 1

修改您的函数以在 post 请求中发送 JSON_DATA header

function sendPostData($url, $post){
 $ch = curl_init($url);
  curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");  
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_POSTFIELDS,$post);
  curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
  curl_setopt($ch, CURLOPT_HTTPHEADER, array(                                                                          
    'Content-Type: application/json',                                                                                
    'Content-Length: ' . strlen($post))                                                                       
   );  
  $result = curl_exec($ch);
  curl_close($ch);  // Seems like good practice
  return $result;
}

在文件中使用

<?php

$json_input_data=json_decode(file_get_contents('php://input'),TRUE);

print_r( $json_input_data);


?>

正如大家所说，不需要 $str_data = json_encode($data);，因为数据已经在 json 中。