php - 在 Laravel Dusk 测试中模拟 HTTP_REFERER？

Question

有没有一种直接的方法可以在 Dusk 测试中模拟 HTTP_REFERER？我正在使用 Laravel\Dusk\Browser 并在各个页面上调用 visit() 方法。这是使用 Selenium 驱动程序。

---

类似于下面的setReferer:

namespace Example\Tests\Browser\Processes\PublicSite;

class SampleBrowser extends Browser {
    use MakesAssertions, ProvidesAdditionalBrowserActions, WaitsForElements;
    public function __construct(RemoteWebDriver $driver, $resolver = null)
    {
        parent::__construct($driver, new ElementResolver($driver,
                            $resolver->prefix ?? 'body'));
    }
}


class SampleTestCase extends BrowserTestCase
{
    /**
     * Test that the deal builder modal shows up.
     */
    public function testRefererRendering()
    {
        $this->browse(function (SampleBrowser $browser) {
            $browser
                // this is the bit that I want
                ->setReferer('https://example.org/') 
                ->visit('/')
                ->waitForLocation('/?came_via=example.org')
                ->assertCookieValue('came_via', 'example.org');
        });
    }
}

Answer 1

Dusk 或任何浏览器/Selenium 测试解决方案都没有实现这种功能，而且它们似乎永远不会实现。

参见 https://github.com/seleniumhq/selenium-google-code-issue-archive/issues/2047

选项 1

导航到 referer URL，然后注入(inject)一个脚本，使页面导航到您要测试的页面。

选项 2

使用代理服务器拦截请求并将 referer 设置为您想要的

https://github.com/j-bennet/selenium-referer

选项 3

如果您正在尝试测试服务器端代码的行为，您始终可以在不使用浏览器完全模拟客户端的情况下对其进行测试。

例如:

<?php

namespace App\Http\Controllers;

use \Illuminate\Http\Request;
use Illuminate\Routing\Controller;

class HomeController extends Controller
{
    public function home(Request $request)
    {
        $referer = $request->header('Referer');
        if ($referer) {
            return redirect()->route('home', ['came_via' => $referer]);
        }
        return view('welcome');
    }
}

和测试用例

<?php

namespace Tests\Feature;

use Tests\TestCase;

class RedirectTest extends TestCase
{
    /**
     * A basic redirect example.
     *
     * @return void
     */
    public function testRedirection()
    {
        // Normal request
        $response = $this->get('/');
        $response->assertStatus(200);

        // Referer check redirection
        $referer = 'http://google.com';
        $response = $this->call('GET', '/', [], [], [], ['HTTP_REFERER' => $referer]);
        $response->assertRedirect('/?came_via=' . urlencode($referer));
    }
}

结果

OK (2 tests, 4 assertions)