php - Symfony 2 从实体管理器获取实体的原始数据

Question

我正在为我的应用程序使用 Sonata admin bundle，一切正常，在我的应用程序中，我有用户和管理员，当我尝试更新用户时，管理员可以添加/编辑/删除用户密码数据有问题从用户表中覆盖。我已经覆盖了管理 Controller 的 preUpdate 方法，我得到了 $object，它有一个用户实体管理器的实例，所以如果用户离开去更新密码并保存数据，密码就会丢失.

public function preUpdate($object)
{
    $Password = $object->getUserPassword();
    if (!empty($Password)) { /* i check here if user has enter password then update it goes well*/
        $salt = md5(time());
        $encoderservice = $this->getConfigurationPool()->getContainer()->get('security.encoder_factory');
        $User = new User();
        $encoder = $encoderservice->getEncoder($User);
        $encoded_pass = $encoder->encodePassword($Password, $salt);
        $object->setUserSalt($salt)->setUserPassword($encoded_pass);
    } else { /* here i try to set the old password if user not enters the new password but fails */
        $object->setUserPassword($object->getUserPassword());
    }
}

当我尝试设置 $object->setUserPassword($object->getUserPassword()); 它得到 null 并将密码更新为 null 它没有得到我试图得到的编辑数据再次访问存储库(如下)以获取密码，但运气不佳

$DM = $this->getConfigurationPool()->getContainer()->get('Doctrine')->getManager()->getRepository("...")->find(id here);

有没有办法在实体管理器中访问当前实体的原始数据

Answer 1

您可以通过获取 doctrine 的 Unit of Work 来访问原始数据。As from docs

You can get direct access to the Unit of Work by callingEntityManager#getUnitOfWork(). This will return the UnitOfWorkinstance the EntityManager is currently using.An array containing theoriginal data of entity

从 Unit of Work 获取密码并在你的 setter 方法中使用

public function preUpdate($object)
{

    $DM = $this->getConfigurationPool()->getContainer()->get('Doctrine')->getManager();
    $uow = $DM->getUnitOfWork();
    $OriginalEntityData = $uow->getOriginalEntityData( $object );
    $Password = $object->getUserPassword();
    if (!empty($Password)) { /* i check here if user has enter password then update it goes well*/
        $salt = md5(time());
        $encoderservice = $this->getConfigurationPool()->getContainer()->get('security.encoder_factory');
        $User = new User();
        $encoder = $encoderservice->getEncoder($User);
        $encoded_pass = $encoder->encodePassword($Password, $salt);
        $object->setUserSalt($salt)->setUserPassword($encoded_pass);
    } else { /* here i try to set the old password if user not enters the new password but fails */
        $object->setUserPassword($OriginalEntityData['Password']);/* your property name for password field */
    }
}

希望一切顺利

Direct access to a Unit of Work